dx × hint: ſ tanxdx = lnsecx + c %3D cos²x

Q: dy/dx=? for  3x4-e2xy+y5=2

A: According to product rule, uv’=u’v+v’u

Q: Specific answer please thank you.

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Q: 4 ry sin (x? + y*)dxdy Find

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Q: Sin JxCosx dx =? (e() b) fx'e dx=?

A: “Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: Find dy xp O y=Sinx Seck

A: y = sinx secx To find dy/dx

Q: J y'+2xyt.xy4 1 =D0; ylo) =

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Q: y+ z)dydxdz is eq

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Q: п sin ydx + cos²xdy = 0; y (÷) =| %3D 4

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Q: dy Find where y = csc-(2x + 6). dx %3D

A: Definition used -                  ddx(csc-1x)=-1x1-x2             Chain rule of derivative -…

Q: dx dy 2 Select one: True False

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Q: Q.43) 2n S Icosx – sinx|dx =

A: Here we have to find solution of given integral

Q: Q7 Find dy using substitution: dx y = csc-(x3 + 1)

A: Put u=x3+1. Then, du=3x2dx Therefore, the expression y=cosec-1(x3+1) becomes,…

Q: (х — 3)dx J («+2)(х + 1)?

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Q: Given z = 11t - 48 and y = 121 sint dy da dy dx2

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Q: d?y Calculate dx² y d²y dx

A: Given, y=2x We have to calculate d2ydx2 First we find first derivative then second.

Q: d?y 1ay +x² cosx +x² cos.x x( dx x> 0. dx?

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Q: x² Ean 2tan' y dx ? tan?

A: Given: The function is ∫x2tan-1xdx. Evaluate the integral using integration by parts.…

Q: Find the solution. 6. (y3 – y?sinx – x)dx + (3xy² + 2ycosx)dy

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Q: dy Solve the equation by Separating the Variables: xy+ 1) + (x - 1): dx Scanned with CamScanner

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Q: dy If y = sin(5x – 7), then dx II

A: Given that, y=sin(5x-7) We have to find first derivative of the given function.

Q: Find y". y310x cos X y'" =D %3D

A: Please refer to the image below.

Q: d'y - 9y = e3* + sin 3x dx?

A: Given differential equation is d2ydx2 - 9y = e3x + sin(3x)

Q: D. Eliminate the arbitrary constant C. 5. y'sinx-2x'y'= Cy?

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Q: dy 7. Find ,y = cos³xsinx? dx

A: Given: y=cos3xsinx2 Formula used: Product rule of derivative: ddxf×g=dfdx×g+dgdx×f Power rule of…

Q: dx y In y || 2.

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Q: dy Find , if y = e-3x tan 5x dx

A: Giveny=e−3xtan5x

Q: dy Find implicitly. dx x?y – e – 7 = o dy xp

A: Given  x2y - ey -7=0

Q: У(xtanx + Inу)dx + tanxdy 3D C

A: The given equation is; y(tan x+ln x)dx+tan xdy=0

Q: -dnd auf for the feaoy) =tan Cx+y). 3xし y

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Q: Find the solution. dy 2y + - :=x?y?sinx dx

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Q: dy dx ycsc 2x = y, .3 tan x

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Q: Q3/ Find ſ Vx * Sin (x³2 -1) dx=? (by substitution)

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Q: L7t2 cos t 8(t)dt

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Q: Q.a) S V9-4x2 dx sec?x secx tanx b) [sec²x dx sec2x+secx+3

A: We Trigonometry substitution method to solve these integration

Q: Evaluate: . dz dy dx x4+4 O T/24 O T148 O tan-(2)/24 O T/96

A: To evaluate ∫02∫0x3∫0y zx4 + 4 dz dy dx

Q: d'y dy - -2xe dx dx

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Q: dy Given x2 + y? = 2022 – 2xy, we have dx %3D O 1 O 2 Other:

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Q: dy 3. dx + y = 2xy²e™

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Q: H.W: Evaluate ,8-2² y² dz dx dy

A: Since you have posted multiple questions, we will solve first question for you. If you want any…

Q: Jo dx 0 1-x² 2 e) fx√x² + 1dx (Hint: use a substitution)

A: Use substitution to solve

Q: Find dy/dx. 2xy3 – x?y = 1 %3D dy xp

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Q: (d) y = tan-1 Vx (e) y = xsinx

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Q: dy ycotx + y³cscx dx

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Q: dx. J x² – 6x + 34

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Q: I need the answer as soon as possible

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: dy No need to simplify. А. Find dx 1. y = cos 3x 2. y = tan? | 3x² 3. y = 5x$ 13

A: We know that  ddxcosax+b= -sinax+bddxax+b ddxtan fx = sec2fxddxfx and ddxxn=nxn-1

Q: d’Y 2) Find dx? X = et et Y = et + t?

A: we have to find the second order derivative

Q: d²y +y = tan x dx?

A: