dx x* +3

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter6: Fractions
Section6.1: Simplifying Fractions
Problem 29WE
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Question

Solve the given using integration using trigonometric substitution.

 

 

dx
+3
Transcribed Image Text:dx +3
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Follow-up Question

Hello, can you please solve the final answer using a right tringle? On there, we are instructed to get the value for the final substitution. Here is the example, please apply it on my given. Thanks.

 

f. [ V² +4r dt = [ {r+2)* – 4dt
= |2 tan e-2 sec 0 tan &de
Solution
Let
(t+2)=2 sec e, dt = 2 sec 0 tan 6de = 4j sec 0 tan ? &de
= 4f sec
= 4[ (sec' e-sec e)de
t= 2 sec e -2, sece
| sec e(sec² e -116e
t+2
VP +4t
sec e tan e +In |sec 0 + tan 6||
-In |sec e + tan
el+C
2
sec 0 tan e – In |sec + tan 6||
= 4
2
= 2(sec e tan e–In |sec e + tan 6|)+C
(t+2/t? +41
(t+2)+\t² +4t
-In
4
2.
Transcribed Image Text:f. [ V² +4r dt = [ {r+2)* – 4dt = |2 tan e-2 sec 0 tan &de Solution Let (t+2)=2 sec e, dt = 2 sec 0 tan 6de = 4j sec 0 tan ? &de = 4f sec = 4[ (sec' e-sec e)de t= 2 sec e -2, sece | sec e(sec² e -116e t+2 VP +4t sec e tan e +In |sec 0 + tan 6|| -In |sec e + tan el+C 2 sec 0 tan e – In |sec + tan 6|| = 4 2 = 2(sec e tan e–In |sec e + tan 6|)+C (t+2/t? +41 (t+2)+\t² +4t -In 4 2.
Solution
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