dx x2 – 64 First, rewrite this with partial fractions: S, da = f 1/(x+8) dx + [ 1/(x-8) dr = log(x+8) log(x-8) +C. 12-64 (Note that you should not include the +C in your entered answer, as it has been provided at the end of the expression.) Next, use the substitution w = r? 64 to find the integral: S da = S x^2-64 dw = +C = In(x^(2)-64) +C. 1 (For the second answer blank, give your antiderivative in terms of the variable w. Again, note that you should not include the +C in your answer.)

dx x2 – 64 First, rewrite this with partial fractions: S, da = f 1/(x+8) dx + [ 1/(x-8) dr = log(x+8) log(x-8) +C. 12-64 (Note that you should not include the +C in your entered answer, as it has been provided at the end of the expression.) Next, use the substitution w = r? 64 to find the integral: S da = S x^2-64 dw = +C = In(x^(2)-64) +C. 1 (For the second answer blank, give your antiderivative in terms of the variable w. Again, note that you should not include the +C in your answer.)

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter5: Exponential And Logarithmic Functions

Section: Chapter Questions

Problem 39CT: The population P (in millions) of Texas from 2001 through 2014 can be approximated by the model...

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