dx xV4x - 1

Q: dx xV2ax – x2 ах

A: This is a problem of integration. Based on the general formula we will solve the question.

Q: 5p2 900 = 0 %3D

A:

Q: tdt 1-t4

A: Topic = Integration

Q: A: ſe2Lnx dx

A: Given: ∫e2lnxdx Simplify the expression. ∫e2lnxdx=∫x2dx

Q: 34x+3 = V3. %3D

A:

Q: cotx + 2cotxsinx=0

A:

Q: (1–2x)/-

A:

Q: 3.) flx) x+2

A:

Q: り ydy + Axdx =0

A: Hey. Thanks for posting your queries. Firstly, let's inform you that as per our Bartleby Guide line,…

Q: 9x+32x dx 3x

A: To determine:

Q: dx 4. xv9+4x2

A: Method:- I  use Trigonometry substitution method to solve the given integral

Q: dx xv64x2–1

A:

Q: Evaluate 1) fx'dx 2) [Vxdx 4 хр, х

A:

Q: 3x Vx - 25

A:

Q: dx xV9 + x2

A: Integral.

Q: S 7dx x(lnx + 1)

A:

Q: fcx)= V16-x?

A: Answer

Q: Simplify

A:

Q: (x +y - 25 4x

A: In this question, we can find the vale of 'x' and 'y'. So use second equation in first and find 'x'…

Q: 2022x dx x2 + 6x + 18

A:

Q: 1x + 2x

A:

Q: Solve for x

A: Square both sides.  On right side use (a-b)^2= a^2 - 2ab + b^2

Q: V8x + 17 = x +3 %3D

A: Consider the equation, To solve for the value x Squaring both sides,

Q: 3X - 250 %3D

A: Solve for x

Q: Differentiate. y= xtan^-1 (3x)

A: Derivative of product uv'=u'v+uv'ddxtan-1x=11+x2

Q: dx XV. xVx2-4

A:

Q: x² + da

A: Evaluate ∫x-1x2x2+255dx=?

Q: V6x + 7 – 2 = x

A:

Q: (2xー)Vxーメ

A:

Q: x5Vx2 + 2dx

A:

Q: faz |(17x – 16)° dx +C - II

A:

Q: dx xVx2/3-7 XVX

A: Given that: ∫dxxx2/3-7

Q: dx xlnx3

A:

Q: X%3D

A:

Q: 3D6 дхду y

A: Topic:- application of integration

Q: Find sec 78 0

A: Given sec 78 0

Q: (V2 – Tx) dx 3 (a) - -3

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: Vx2–25 dxl 5x

A: Consider the integral

Q: (DE- 6D + 25)у %3D0 y =

A:

Q: dx xV4x-1

A: To find: The integral of ∫dxx4x-1. Formula used: Integration formula: ∫dxx2+1=tan-1x+C

Q: Evaluate ' (4x + 2)dxdy.

A: Since you have asked multiple questions so as per our guidelines we will solve the first question…

Q: 12a³+10a²

A:

Q: 8dx 5. S V16+x²

A:

Q: +9z dz

A:

Q: Vx ER (|x – 3| > 3 → x² > 6x)

A:

Q: -8x dx 1x4

A:

Q: dx x²V6x – x²

A: To solve the given integral problem.

Q: Find ∫^4 2 (6x5+4x2)dx

A:

Q: (a) log5x + logs (x + 5) = logs(3x+ 15) %3D

A:

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.