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- Which of the following is not a Python list method?a) index b) insert c) get d) pop9.5 Create a SinglyLinkedList method named reverse that reverses the order of the list's items. This method should be harmful in the sense that it should change the list on which it functions. 9.6 Create a DoublyLinkedList method named reverse that reverses the order of the list's items. This procedure should be destructive.9.7 Create a CircularList method named reverse that reverses the order of the elements in the list. This procedure should be destructive.7-Write a procedure that returns the list that contains everything except for the last element of the given (nonempty) list. For example, (last-element ‘(a (b c ) (d)) ) returns (a (b c)). For example, (last-element ‘(a (b c ) (d) ) ) returns (a (b c)) . Then, Manually trace your procedure with the provided example.
- 1. How can values in a pandas Series method be accessed as a Python list? using the tolist) method using the getlist() method using the list constructor any of these 2. For a DataFrame df, how can its first row be accessed? df[O] df.loc[0] df.iloc[0] any of thesehow can i remove the spaces at the end of each line in my code ? code: def load_course(course_name):try:file = open(course_name+'.txt')return file.readlines()except FileNotFoundError as e:return None def word_wrap_text(text,lineWidth):words = list(text.split())linelen = 0lines = []line = ''for word in words:if linelen + len(word) > lineWidth:lines.append(line)line = ''line += word + ' 'linelen = len(line)if line !='':lines.append(line)return '\n'.join(lines) def enhanced_word_wrap_text(text,lineWidth):words = list(text.split())linelen = 0lines = []line = ''for word in words:if linelen + len(word) + 1 > lineWidth:lines.append(line + word[:lineWidth-linelen])line = word[lineWidth-linelen:] + ' 'else:line += word + ' 'linelen = len(line)if line != '':lines.append(line)return '\n'.join(lines) lineWidth = int(input("")) while True:course = input("")if course == 'q':breaklines = load_course(course)if lines == None:print('Unable to load course information for course',course)else:for…how do i get this code to work properly function noSql(list, query) { var result=[]; var match = matchmaker(query); for(var i=0; i<list.length; i++) { var temp = list[i]; if(match(temp)) { result.push(temp); } } return result;} these are the instructions and examples somebody answered this incorrectly please do not copy that answer thank you!! noSql( list, query ) This function accepts a list of elements and an object known as the query. The method returns a list of all elements that have each of the key/value properties of the query. Examples var objects = [ { public : true, name : "Lion King" }, { public : true, name : 'Dumbo' }, { public : false, name : 'Lion King' }, { name : 'Xeon', rating : 5 } ]; noSql( objects, { public:true } ) should return this [ { public:true, name:'Lion King' }, { public:true, name:'Dumbo'}] noSql( objects, { name:'Lion King' } ) should return this [ { public:true, name:'Lion King' }, {…
- Make a dictionary, the student's name is the key (a string) and the student's test scores is the value (a list). So it should be a dictionary with six key value pairs in it. Here is data to use. Brian,94,89,92 Rachel,100,90,65 Jon,67.5,95,100 Brit,0,78,80 Greg,65,100,78 Andrea,55.5,67,79 1. Now print the dictionary data using a loop that starts with for key, value in. 2. Now print the dictionary data using a loop that starts with for key in 3. Find and print out Rachels second score (should be a 90) 4. This one is a little tricky, a little mind-bender. Make a new dictionary. Using the dictionary you made from above,. the new dictionary should consist of the key is the name of the person, and the value is just the average of their scores. So it’s six key value pairs but instead of the value being a list like the first problems, this time it's just their average (which you compute from their scores in the other dictionary. Print the new dictionary out. 5. You…In which of the following linked list there will be no beginning and ending? a. Depends on the Problem. b. Circular Linked List. c. Double Linked List. d. Single Linked List. Clear my choiceBefore adding a new term to a dictionary you should A. Make it a tuple. B. Make it a list C. Make sure the dictionary key doesn’t already exist D. Place it in quotes to make it a string Which one?
- Complete the method “readdata”. In this method you are to read in at least 10 sets of student data into a linked list. The data to read in is: student id number, name, major (CIS or Math) and student GPA. You will enter data of your choice. You will need a loop to continue entering data until the user wishes to stop. Complete the method “printdata”. In this method, you are to print all of the data that was entered into the linked list in the method readdata. Complete the method “printstats”. In this method, you are to search the linked list and print the following: List of student’s id and names who are CIS majors List of student’s id and names who are Math majors List of student’s names along with their gpa who are honor students (gpa 3.5 or greater) All information for the CIS student with the highest gpa (you may assume that different gpa values have been entered for all students) CODE (student_list.java) You MUST use this code: package student_list;import…????????: Consider this following dictionary of lists for your question. So just copy this dictionary to your editor. number_lists = {1: [2,6,4], 2: [51,6,89], 3: [23,9,32], 4: [31,53,8], 5: [7,44,55]} Take an integer from the user (The number should be greater than 0), add up all the digits. If the summation of all the digits is even then find the summation of all the even values of all the odd keys from the given dictionary. If the summation is odd then find the summation of all the odd values of all the even keys from the given dictionary. Then print the summation. Sample Input 1: 441 Sample Output 1: 224 Explanation 01: The summation of digits of given input is 4+4+1 = 9 which is an odd number. That’s why we need to find the even keys from the dictionary which are {2: [51,6,89], 4: [31,53,8] } and sum up the odd values from these even keys which results in 51+89+31+53 = 224. Sample Input 2: 88 Sample Output 2: 88 Explanation 02: The summation of digits of given…????????: Consider this following dictionary of lists for your question. So just copy this dictionary to your editor. number_lists = {1: [2,6,4], 2: [51,6,89], 3: [23,9,32], 4: [31,53,8], 5: [7,44,55]} Take an integer from the user (The number should be greater than 0), add up all the digits. If the summation of all the digits is even then find the summation of all the even values of all the odd keys from the given dictionary. If the summation is odd then find the summation of all the odd values of all the even keys from the given dictionary. Then print the summation. Sample Input 1: 441 Sample Output 1: 224 Explanation 01: The summation of digits of given input is 4+4+1 = 9 which is an odd number. That’s why we need to find the even keys from the dictionary which are {2: [51,6,89], 4: [31,53,8] } and sum up the odd values from these even keys which results in 51+89+31+53 = 224. Sample Input 2: 88 Sample Output 2: 88 Explanation 02: The summation of digits of given…