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E Fe Pt/Fe³+ (0.1600 M), Fe2+(0.0700 M) // Hg2+ (0.0350 M)/Hg EHg2+ = +0.854 V O +0.020 V spontaneous reaction -0.019 V nonspontaneous reaction O + 0.019 V spontaneous reaction O-0.020 V nonspontaneous reaction

E Fe Pt/Fe³+ (0.1600 M), Fe2+(0.0700 M) // Hg2+ (0.0350 M)/Hg EHg2+ = +0.854 V O +0.020 V spontaneous reaction -0.019 V nonspontaneous reaction O + 0.019 V spontaneous reaction O-0.020 V nonspontaneous reaction

Fundamentals Of Analytical Chemistry
Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter19: Applications Of Standard Electrode Potentials
Section: Chapter Questions
Problem 19.8QAP
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Calculate the theoretical cell potential of the following cells. If the cell is short-circuited, indicate the direction of the spontaneous cell reaction. (Paste your computation in the class notebook. No solution, No credit) Pt/Fe³+ (0.1600 M), Fe²+ (0.0700 M) // Hg2+(0.0350 M)/Hg EHg2+ = +0.854 V E Fe3+=+0.771 V +0.020 V spontaneous reaction -0.019 V nonspontaneous reaction O +0.019 V spontaneous reaction -0.020 V nonspontaneous reaction
Transcribed Image Text:Calculate the theoretical cell potential of the following cells. If the cell is short-circuited, indicate the direction of the spontaneous cell reaction. (Paste your computation in the class notebook. No solution, No credit) Pt/Fe³+ (0.1600 M), Fe²+ (0.0700 M) // Hg2+(0.0350 M)/Hg EHg2+ = +0.854 V E Fe3+=+0.771 V +0.020 V spontaneous reaction -0.019 V nonspontaneous reaction O +0.019 V spontaneous reaction -0.020 V nonspontaneous reaction
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