ead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is eased from rest at a height h = 3.40R. R (a) What is its speed at point ? (Use the following as necessary: the acceleration due to gravity g, and R.) √2.8gR v= (b) How large is the normal force on the bead at point if its mass is 5.50 grams? magnitude XN direction downward

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter7: Conservation Of Energy
Section: Chapter Questions
Problem 3P: Review. A bead slides without friction around a loop-the-loop (Fig. P7.3). The bead is released from...
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A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is
released from rest at a height h = 3.40R.
R
(a) What is its speed at point ? (Use the following as necessary: the acceleration due to gravity g, and R.)
V = √ 2.8gR
(b) How large is the normal force on the bead at point if its mass is 5.50 grams?
magnitude
X N
direction downward ✓
Transcribed Image Text:A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead slides without friction around a loop-the-loop (see figure below). The bead is released from rest at a height h = 3.40R. R (a) What is its speed at point ? (Use the following as necessary: the acceleration due to gravity g, and R.) V = √ 2.8gR (b) How large is the normal force on the bead at point if its mass is 5.50 grams? magnitude X N direction downward ✓
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