13 please using by this formula sheet easy way to explain v2Circular motion: a =RWPavr =AtFast = ma;Weight: F = mg, ;g = 9.8 m/s²;1(Kinetic energy: K = -m v²;2Potential energy: Ug = mgyE = EE = U+KRotational motion:1 rev = 2n rad;V = 0r;= m?r;at = ar;a, =0 = 0o + at;0 = 0o t+20a = 0² - mo²K=-To t =rFsing;T =rxF;Στ-Ια;Ipointmass = mr?1Icy=2 mR 2Idisk =mR 21+RinIhoop = mR?1Irod(center) =1Ired(end) = mL32Iball = mR?2Ishell = mR?312 mL?work: W=t0; K--lo ?I= Icom + MD?P- dWdt2W =WPavr =AtRolling:Veom = RoK =2m Veom 22T= f,RF,max = H,FnIncline: F=mgsin0 F=mgcos0Angular momentum;Lpolnt mass =m rxvL=mrvsin 0;L=m (r,vy - ryV,)kL= IoLI = LrI, 01 =I 202m,X1+m2X2X com =miyi+m2y2m, +m2y com =m1 +m2 SAMPLE EXAM 3PHYSICS 111SPRING 202212. A 4-kg ball moving to the right at 12 m/s collides elastically with a 2-kg ball moving to the left at 6 m/s. What are thespeeds of the 4-kg and the 2-kg balls after the collision?A) 4 m/s and 10 m/sB) 6 m/s and 12 m/sC) 12 m/s and 6 m/sD) 8 m/s and -8 m/sE) 10 m/s and -4 m/s13. A 2-kg block is placed at the top of a 5-m high, frictionless ramp and is released from rest. At the bottom of the rampthe 2-kg block collides with a 1-kg block that is initially at rest. The blocks stick together. What is the velocity of theblocks after the collision?A) 3.3 m/sB) 6.6 m/sC) 9.9 m/sD) 10.10 m/sE) There is not enough information given14. A potential energy function is given below. At what point would an object experience a force in the positive xdirection?ac dA) aB) bС) сD) dE) in the region from 0 to a, and from c to infinity15. A 3-kg box is moving at 6.0 m/s atop a hill that is 5.0 m above a flat frictionless surface. It descends the hill (alsofrictionless) and at the bottom of the hill contacts an ideal spring, which compresses 1.53 m before stopping. What is thespring constant k ?A) 172 N/mB) 225 N/mC) 344 N/mD) 450 N/mE) 980 N/m

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Science

Physics

ec

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter6: Momentum, Impulse, And Collisions

Section: Chapter Questions

Problem 63AP: A 2.0-g particle moving at 8.0 m/s makes a perfectly elastic head-on collision with a resting 1.0-g...

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What is the velocity of a 900-kg car initially moving at 30.0 m/s, just after it hits a 150-kg deer initially running at 12.0 m/s in the same direction? Assume the deer remains on the car.
A wooden block of mass M rests on a table over a large hole as in Figure P9.39. A bullet of mass m with an initial velocity of vi is fired upward into the bottom of the block and remains in the block after the collision. The block and bullet rise to a maximum height of h. (a) Describe how you would find the initial velocity of the bullet using ideas you have learned in this chapter. (b) Find an expression for the initial velocity of the bullet. Figure P9.39 Problems 39 and 40.
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