either evaluate or explain why limit does not exist.lim f(x) as x --> 0 for (5 +2x+sinx) / (6cos x)I did substitution (5+2(0) + sin(0)) / 6cos(0) = (5+0+1) / (6 * 1)....BUT the book had (5+0+0) / (6 * 1).....struggling with why sin(0) = 1 and cos x = 0....as I thought when you find x the answer is y. so for sin(0) where x = 0 then why would this be 0? and same for cos(0) where x = 0, y would be 1 or -1??what is the logic behind how they are getting the numbers
either evaluate or explain why limit does not exist.
lim f(x) as x --> 0 for (5 +2x+sinx) / (6cos x)
I did substitution (5+2(0) + sin(0)) / 6cos(0) = (5+0+1) / (6 * 1)....BUT the book had (5+0+0) / (6 * 1).....
struggling with why sin(0) = 1 and cos x = 0....as I thought when you find x the answer is y. so for sin(0) where x = 0 then why would this be 0? and same for cos(0) where x = 0, y would be 1 or -1??
what is the logic behind how they are getting the numbers
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