# Electricity Costs. The monthly service charge for electricity for a residential customer who is using the local electric utility’s Two Period Plan is \$4.10. There is a charge of \$0.148 per kilowatt hour (kWh) of electricity used during “on peak” hours in a month (x1), and a charge of \$0.046 per kWh of electricity used during “off peak” hours in a month (x2). Let y denote the cost of electricity during a month.a. Obtain the equation that expresses y in terms of x1 and x2.b. Find the y-intercept, b0, and partial slopes, b1 and b2, of the linear equation in (a).c. Find the cost for a customer who uses 200 kWh of electricity during “on peak” hours and 800 kWh of electricity during “off peak” hours during a month.

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Electricity Costs. The monthly service charge for electricity for a residential customer who is using the local electric utility’s Two Period Plan is \$4.10. There is a charge of \$0.148 per kilowatt hour (kWh) of electricity used during “on peak” hours in a month (x1), and a charge of \$0.046 per kWh of electricity used during “off peak” hours in a month (x2). Let y denote the cost of electricity during a month.

a. Obtain the equation that expresses y in terms of x1 and x2.

b. Find the y-intercept, b0, and partial slopes, b1 and b2, of the linear equation in (a).

c. Find the cost for a customer who uses 200 kWh of electricity during “on peak” hours and 800 kWh of electricity during “off peak” hours during a month.

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Step 1

Solution: We are given that:

The monthly service charge for electricity for a residential customer who is using the local electric utility’s Two Period Plan is \$4.10. There is a charge of \$0.148 per kilowatt hour (kWh) of electricity used during “on peak” hours in a month (x1), and a charge of \$0.046 per kWh of electricity used during “off peak” hours in a month (x2)

Step 2

a. Obtain the equation that expresses y in terms of x1 and x2.

Answer: Let y be the cost of electricity during a month, x1 be the cost of electricity during "on peak" hours in a month and x2 be the cost of electricity during "off peak" hours in a month.

We are given that the monthly service charge for electricity for a residential customer who is using the local electric utility’s Two Period Plan is \$4.10, therefore, the intercept of the equation is 4.10

Also, we are given that there is a charge of \$0.148 per kilowatt hour (kWh) of electricity used during “on peak” hours in a month, therefore, the partial slope of x1 is 0.148

And the partial slope of x2 is 0.046

Therefore, the equation that expresses y in terms of x1 and x2 is:

Step 3

b. Find the y-intercept, b0, and partial slopes, b1 and b2, of the linear equation in ...

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