Ely = MAr +RĄx² – P(x – )² + C1 Ely = Ma¤² + ¿RAr – ¿P(x – 4° +C1- Let P=75 kN, L = 17 m
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- ) Determine the reactions at thesupports (Note: “A” is fixed and“B” can be idealized as a roller).The moment of inertia (2nd momentof area) for each segment is shownin the figure. Let E = 29,000 ksi.Select the reaction at B as theredundant.2. The beam AB shown is supported at A and B. the beam is loaded with three fixed concentrated loads and an overhead hoist carrying a load W. P1 P2-320 KN. P3-200 KN and W-500 KN A. Find the distance of W from A in meters if the resultant of the external loads is at the midspen B. What is the reaction at A when W is at midspan?The reaction at A is 60.0 KN-m and the reaction at D is 60.0 KN-m The moment due to the reaction force at A is 120.0 KN-m The moment due to the adjusted line load is -60.0 KN-m the moment due to line load that cancels out the additional load from the adjusted line load is 60.0 KN-m QUESTIONS (Please see 2nd attached photo for reference) What is the Area at A1? (the shaded portion) 367.5 KN-m² 643.125 KN-m² 120.0 KN-m² 735.0 KN-m² What is the Area at A2? (the shaded portion) –214.375 KN-m² –40.0 KN-m² –625.0 KN-m² –321.563 KN-m² What is the Area at A3? (the shaded portion) 16.875 KN-m² 135.0 KN-m² 40.0 KN-m² 25.313 KN-m² What is the deviation of point A to the tangent drawn from the midspan, tA/Midspan? What is the deflection at midspan, δmidspan?
- A 250mm x 300mm beam 7m long is supported at its end and its midspan. It carries a uniformloadof 9KN/m excluding its own weight. E = 13.8 GPA. Weight of wood is 9.5 KN/m^3. If the allowable deflection is12mm. a. Compute the reaction at Midspanforce@ D=40kips. I have provided the reactions. Pls continue Asap. Thanks. Use moment distribustion methodThe frame is used to support the wood deck in a residential dwelling. Sketch the loading that acts along the members BG and ABCD. a) Set b = 4.5 m, a = 2.4 m. Use Live Load = 1.92 kPa. b) Set b=2.4m, a=2.4m. Use Live Load = 1.92 kPa
- Given the Statically Determinate Simple Beam as shown below withinternal hinged at Point B and additional external support at Point D (0.9 m fromPoint A).Determine the following:a.) The External Reaction at Point A.b.) The Internal Reaction at Point B.c.) The External Reaction at Point C.d.) The External Reaction at Point D.5-3 Beam AB carries a uniformly distributed load of intensity ωo = 30 N/m as shown in theFigure. The beam is made up of a material with an elastic modulus E = 50 GPa and has asquare cross-section of side 10 mm, both of which are constant along the length of thebeam. Determine the reactions at A and B. (Please use the method of superposition tofind the deflection of beam13 - Support reactions will be found in the gerber beam whose loading condition is given in the figure. A is the fixed support, the G point is the intermediate joint, and the B support is the sliding joint. Distributed loads on the beam q1= 9 kN ⁄ m, q2= 6 kN ⁄ m, beam dimensions a = 3 m, b = 2 m. Accordingly, Bx = ?a) 45B) 6C) None.D) 0E) 19.5
- The two cylinders shown are identical and weighs 1000 N. The inclined smooth surface is 33° from the horizontal. Determine the Reaction at Point A. 3 deimal points and FBDHelp ASAP P= 541kN determine vertical reaction at A(in kN) 3 decimalsFor the given loads w = 36 KN/m and M=90 KN.m is supported as shown by a roller at D and a hinge at D 1- Magnitude of reaction at D is (KN) : (a. 72 - b. 180 - c. 144 - d. 216 - e. 252 ) 2- Magnitude of reaction at A is (KN): (a. 72 - b. 108 - c. 252 - d. 36 - e. 180 ) 3- Bending moment just to the right of B (KN.m) : (a. -36 - b. -54 - c. -72 - d. -90 - e. -108) 4-Find Shear force just to the right of D 5- Find Shear force just to the left of D 6- Find Maximum absolute value of bending moment (KN.m) is