Encrypt the animal name pangolin using the letter to number correspondence abcdef shijk 1 mnopar stuvw x y z e 1 2 3 4 5 678 9 18 11 12 13 14 15 16 17 18 19 28 21 22 23 24 25 and the encrypton function f (n) = (n+ 20) mod 26 The answer will be a nonsense word (no numbers). Decrypt An animal name was encrypted with the scheme described above. The encrypted animal name is urifinf . What is the animal name?
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- Substitution ciphers are encryption/decryption algorithms that replace one letter or number with another. The first attested use of a substitution cipher in military affairs was by Julius Caesar, described by him in Gallic Wars (cf. Kahn pp83-84). In caesar cipher , you replace each letter by 3rd letter on. If it is out of bound (later than Z), then round to the head (letter A) and continue the shift. For example:meet me after the toga party PHHW PH DIWHU WKH WRJD SDUWB Please write a program in Java to implement the Caesar Cipher: a. Implement the encryption algorithm. Ask the user to input one all lower case normal sentence (called plaintext) using the nextLine method, and then output the encrypted text (called ciphertext). b. Implement the decryption algorithm. Ask the user to input one encrypted sentence (i.e. ciphertext) using the nextLine method, and then output the decrypted text (i.e. plaintext).FIX ME: In C language Update this function to display the string of 16 bits using the following pattern: 11111 111111 11111 (5) (6) (5) */ void printbits(unsigned short wrd) { int testbit(unsigned short wrd, int bit_to_test); int i; for (i = 15; i >= 0; i--) { printf("%1d", testbit(wrd, i)); if (!(i % 4)) printf(" "); } printf("\n"); }A data.frame: 6 × 2 train_label distance <fct> <dbl> 2 1 3.9301694 3 1 5.8230155 4 1 0.4738137 5 1 1.3395091 6 1 0.4699036 7 1 0.9272197 Write a Python code to sort collectbased on distance in ascending order (from lowest to highest) and only show the first 9 rows and call it Nine_neighbors
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- Computer Science you are given a string X of length n and another string Y of length m ≤n. Say,the indexes p1, p2, p3, p4 and q1, q2, q3, q4 form two sub-sequences, i.e., 0 ≤ p1 < p2 < p3 < p4 < nand 0 ≤q1 < q2 < q3 < q4 < n; then, they are non-overlapping if p4 < q1.The task is to count the maximum number of non-overlapping sub-sequences of X that are thesame as Y . Thus, if X = GAXTYAWBGTAUGBTABGRGTAXB and Y = GTAB, then the answer is3 as shown by the red fonts. We cannot select the underlined GTAB as it overlaps with a red GTAB(i.e., among overlapping sub-sequences, you can select only one of them).Describe an O(m + n) time algorithm to obtain the count. Write a pseudo-code.Using foldl, define a function num2int :: [Int] -> Int -> Int that converts a list of numbers and the number n into an integer of base n. >num2int [3,4,5,6] 10 3456 >num2int [1,1,0,1,0,0,0,1,0,1,0,1,1,0] 2 3456 num2int :: [Int] -> Int -> Int num2int x y = foldl (\acc (a,b) -> ___a___ + b*y^a) 0 (___b___ (\x y ->(x,y)) [0..] (___c___ x)) fill in blank spaces of a , b , and cA number of the form a + ib, in which i2 = -1 and a and b are real numbers, is called a complex number. We call the real part and b the imaginary part of a + ib. Complex numbers can also be represented as ordered pairs (a, b). The addition and multiplication of complex numbers are defined by the following rules: (a + ib) + (c + id) = (a + c) + i(b + d ) (a + ib) * (c + id) = (ac - bd) + i(ad + bc) Using the ordered pair notation, these rules are written as: (a, b) + (c, d) = ((a + c), (b + d )) (a, b) * (c, d) = ((ac - bd ), (ad + bc)) C++ has no built-in data type that allows us to manipulate complex numbers. Construct a data type, complex Type, that can be used to process complex numbers. Overload the stream insertion and stream extraction operators for easy input and output. We will also overload the operators + and * to perform addition and multiplication of complex numbers. If x and y are complex numbers, we can evaluate expressions such as x + y and x * y.