
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Using only string methods, devise a way to determine if a nucleotide sequence is a palindrome in the sense that it is equal to its own complementary sequence read backwards. For example, the sequence TGGATCCA is palindromic because its complement is ACCTAGGT, which is the same as the original sequence backwards. The complementary base pairs are (A,T) and (C,G)
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- Longest Common Subsequence:ExampleLCS for input Sequences “ABCDGH” and “AEDFHR” is “ADH” of length 3.LCS for input Sequences “AGGTAB” and “GXTXAYB” is “GTAB” of length 4.Implementation in Java.arrow_forwardA cyclic permutation of a string takes the string and shifts each letter forward by a constant amount k, with letters that shift off the end of the string coming back in at the front. For instance, the cyclic permutations of the string ABCDEF are FABCDE, EFABCD, DEFABC, CDEFAB, BCDEFA, and ABCDEF itself. A reverse cyclic permutation is the reverse of a cyclic permutation; for instance ABCDEF has the reverse cyclic permutation DCBAFE amongst others. Given two strings S and S", provide a linear time algorithm to decide whether S is a reverse cyclic permutation of S'.arrow_forwardIf we are given with the two strings we have to find the longest common sub-sequence present in both of them.ExampleLCS for input Sequences “ABCDGH” and “AEDFHR” is “ADH” of length 3.LCS for input Sequences “AGGTAB” and “GXTXAYB” is “GTAB” of length 4.Implementation in Javaarrow_forward
- Given the following CFG S → OB A → 1AA|A B → OAA The following strings can be generated except i. 001 ii. 000 iii.0011 iv. 01 O A. i and iii O B. i and ii O C. iv only O D. ii onlyarrow_forwardRecall that a bit string is a string of Os and 1s Describe the following sequence recursively. Include initial conditions and assume that the sequences begin with a₁. a₁ is the number of ways to go down an n-step staircase if you go down 1, 2, or 3 steps at a time.arrow_forwardWrite Algorithm to Conversion from an Arabic number to a modern Roman number.in: decimal number n (0 ≤ n)out: sequence R = s0, s1,...,s12 representing the structure of the Roman number (Ri = number of primitives Vi in n for i ∈ [0, 12])constant: sequence P = 1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1 of primitive Roman numberslocal: remainder x to be converted (0 ≤ x ≤ n); coefficient c for a primitive Romannumbers (for other than P0, 0 ≤ c ≤ 3)arrow_forward
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