Encrypt the message " HALT " by %3D translating the letters into numbers (via A = 0, B = 1, C = 2, D = 3, E = 4, F = 5, G = 6, H = 7,1 = 8, J = 9, K = 10, L = 11, M = 12, N = 13, 0 = 14, P = 15, Q = 16, R = 17, S = 18, T = 19, U = 20, V = 21, W = 22, X = 23, Y = 24, Z = 25 %3D %D %3D %| %3D and then applying the encryption function given, and then translating the numbers back into letters. (a) f(p) = (p + 4) mod 26 (b) f(p) = (p + 10) mod 26 (c) f(p) = (p + 3) mod 26 %3D

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.3: Rules For Addition
Problem 7P
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Encrypt the message " HALT " by
translating the letters into numbers
(via
A = 0, B = 1, C = 2, D = 3, E = 4, F = 5, G = 6, H = 7,1 = 8,
J = 9, K = 10, L = 11, M = 12, N = 13,0 = 14, P = 15, Q = 16, R = 17,
S = 18, T = 19, U = 20, V = 21, W = 22, X = 23, Y = 24, Z = 25
%3D
%3D
%3D
%3D
and then applying the encryption function given, and
then translating the numbers back into letters.
(a) f(p) = (p + 4) mod 26
(b) f(p) = (p + 10) mod 26
(c) f(p) = (p + 3) mod 26
Transcribed Image Text:Encrypt the message " HALT " by translating the letters into numbers (via A = 0, B = 1, C = 2, D = 3, E = 4, F = 5, G = 6, H = 7,1 = 8, J = 9, K = 10, L = 11, M = 12, N = 13,0 = 14, P = 15, Q = 16, R = 17, S = 18, T = 19, U = 20, V = 21, W = 22, X = 23, Y = 24, Z = 25 %3D %3D %3D %3D and then applying the encryption function given, and then translating the numbers back into letters. (a) f(p) = (p + 4) mod 26 (b) f(p) = (p + 10) mod 26 (c) f(p) = (p + 3) mod 26
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