DIRECTION . Find the length of the following confidence interval1. р3D 0.25n = 300CL = 95%2. p = 0.35= 320CL =90%%3D3. p = 0.48n = 210CL =92%4. p = 0.385. o = 0.45= 0.157. o = 0.25= 220CL93%%3D!!n= 41CL = 99%6. 0 =n= 100CL = 99%= 50CL95%n8. s = 1.35n= 25CL98%%3D9. s = 4.44= 18CL90%%3D10.2.= 3CL =99%n = 26

According to guidelines we solve only first question when given. questions are different.

Answered: ength ing 1. p = 0.25 n = 300 CL = 95%…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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