es 13-18, pplied to orem can such that 34 2 2 cost of placi COST Motion Along a Line In Exercises 35 and 36, the function S(t) describes the motion of a particle along a line. (a) Find the velocity function of the particle at any time t 0. (b) Identify the time interval (s) on which the particle is moving in a positive direction. (c) Identify the time interval(s) on which the particle is moving in a negative direction. (d) Identify the time(s) at per ye billions of dol/ table,where / is 2006. (Source 6 53. Modeling D why not. which the particle changes direction. 35. S(t) = 3t - 2t 36. s(t) = 63 -8t +3 521 8t+3 Finding Points of Inflection In Exercises 37-42, find t. points of inflection and discuss the concavity of the granh of 11 the function. 705 D 37. f(x) = x3 -9x2 38. f(x) = 6x4 - r (a) Use the regre 39. g(x) = xx +5 a model of th 40. f(x) = 3x -5x3 eorem be D = att + b 41. f(x) = x + cos x,. 2 for the data. 42. f(x) = tan (0, 2) 42 (b) Use a graphin (c) For the years Using the Second Derivative Test In Exercises 43-48 find all relative extrema of the function. Use the Second Derivative Test where applicable. indicate that maximum? W (d) For the years mine the 43. f(x) = (x + 9)2 m on the indicate that th 44. f(x) = x4 - 2x2+6 at the greatest 3х + 1 45. g(x) = 2x2(1 -x) 46. h(t) = t - 4 t+1

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.7: Operations On Functions
Problem 50E
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43

es 13-18,
pplied to
orem can
such that
34
2
2
cost of placi
COST
Motion Along a Line In Exercises 35 and 36, the function
S(t) describes the motion of a particle along a line. (a) Find the
velocity function of the particle at any time t 0. (b) Identify
the time interval (s) on which the particle is moving in a positive
direction. (c) Identify the time interval(s) on which the particle
is moving in a negative direction. (d) Identify the time(s) at
per ye
billions of dol/
table,where / is
2006. (Source
6
53. Modeling D
why not.
which the particle changes direction.
35. S(t) = 3t - 2t
36. s(t) = 63 -8t +3
521
8t+3
Finding Points of Inflection In Exercises 37-42, find t.
points of inflection and discuss the concavity of the granh of
11
the function.
705
D
37. f(x) = x3 -9x2
38. f(x) = 6x4 - r
(a) Use the regre
39. g(x) = xx +5
a model of th
40. f(x) = 3x -5x3
eorem be
D = att + b
41. f(x) = x + cos x,. 2
for the data.
42. f(x) = tan
(0, 2)
42
(b) Use a graphin
(c) For the years
Using the Second Derivative Test In Exercises 43-48
find all relative extrema of the function. Use the Second
Derivative Test where applicable.
indicate that
maximum? W
(d) For the years
mine the
43. f(x) = (x + 9)2
m on the
indicate that th
44. f(x) = x4 - 2x2+6
at the greatest
3х + 1
45. g(x) = 2x2(1 -x)
46. h(t) = t - 4 t+1
Transcribed Image Text:es 13-18, pplied to orem can such that 34 2 2 cost of placi COST Motion Along a Line In Exercises 35 and 36, the function S(t) describes the motion of a particle along a line. (a) Find the velocity function of the particle at any time t 0. (b) Identify the time interval (s) on which the particle is moving in a positive direction. (c) Identify the time interval(s) on which the particle is moving in a negative direction. (d) Identify the time(s) at per ye billions of dol/ table,where / is 2006. (Source 6 53. Modeling D why not. which the particle changes direction. 35. S(t) = 3t - 2t 36. s(t) = 63 -8t +3 521 8t+3 Finding Points of Inflection In Exercises 37-42, find t. points of inflection and discuss the concavity of the granh of 11 the function. 705 D 37. f(x) = x3 -9x2 38. f(x) = 6x4 - r (a) Use the regre 39. g(x) = xx +5 a model of th 40. f(x) = 3x -5x3 eorem be D = att + b 41. f(x) = x + cos x,. 2 for the data. 42. f(x) = tan (0, 2) 42 (b) Use a graphin (c) For the years Using the Second Derivative Test In Exercises 43-48 find all relative extrema of the function. Use the Second Derivative Test where applicable. indicate that maximum? W (d) For the years mine the 43. f(x) = (x + 9)2 m on the indicate that th 44. f(x) = x4 - 2x2+6 at the greatest 3х + 1 45. g(x) = 2x2(1 -x) 46. h(t) = t - 4 t+1
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