I need help on 71.
es h= 0 and h T 71. A torus (doughnut) Find the volume of the torus formed when the circle of radius 2 centered at (3, 0) is revolved about tha y-axis. Use geometry to evaluate the integral. e y A -3 21 b- is. e r, x 2U60 72. Which is greater? Let R be the region bounded by y = r'and = the
Equation fo the circle centred at (3, 0) and with radius 2 will be:
(x – 3)2 + (y – 0)2 = 22 = 4
Or, (x – 3)2 + y2 = 4
Please see the white board.
(ax-3)2y x = 3+ - 1/2
Please see the white board.
T(-rdy Volume 2 /4- P) # (3+ /4- 22+(3-\/4-) - 2 2 dy 6/4- y2 - (9 4- y6/4-y2dy T[(94 Jo J4
Please see the white board.
Now the geometry can be used to evaulate this integral as per any of the two methods below:
Method 1: The area under integral is nothing but the area of the one quarte...
-2 2 12T /4 2dy= 247 V4dy Volume V 2
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