EspañolA lighthouse sits at the edge of a cliff, as shown. A ship at sea level is 825 meters from the base of the cliff. The angle of elevation from sea level to the base ofthe lighthouse is 37.2°. The angle of elevation from sea level to the top of the lighthouse is 38.3°. Find the height of the lighthouse from the top of the cliff.Do not round any intermediate computations. Round your answer to the nearest tenth.Note that the figure below is not drawn to scale.meters38.3°37.2825 metersExplanationCheckO 2021 McGraw Hill LLC. AllRights Reserved. Terms of UseI Privacy Center AccessibilityMacBook Air435TQRAFGHKVвNaltaltoptioncomm ndcommandoption

Answered: Image /qna-images/answer/beecb067-3391-44f8-826c-29e9d13dd01f.jpg

Español A lighthouse sits at the edge of a cliff, as shown. A ship at sea level is 825 meters from the base of the cliff. The angle of elevation from sea level to the base of the lighthouse is 37.2°. The angle of elevation from sea level to the top of the lighthouse is 38.3°. Find the height of the lighthouse from the top of the clif. Do not round any intermediate computations. Round your answer to the nearest tenth. Note that the figure below is not drawn to scale. meters 38.3 37.2 825 meters

Español A lighthouse sits at the edge of a cliff, as shown. A ship at sea level is 825 meters from the base of the cliff. The angle of elevation from sea level to the base of the lighthouse is 37.2°. The angle of elevation from sea level to the top of the lighthouse is 38.3°. Find the height of the lighthouse from the top of the clif. Do not round any intermediate computations. Round your answer to the nearest tenth. Note that the figure below is not drawn to scale. meters 38.3 37.2 825 meters

Mathematics For Machine Technology

8th Edition

ISBN:9781337798310

Author:Peterson, John.

Publisher:Peterson, John.

Chapter23: Basic Calculations Of Percentages, Percents, And Rates

Section: Chapter Questions

Problem 5A: The length, L, of the standard 82° included angle drill can be calculated using the formula L=0.575...

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