Estimate the number of steps you would have to take to walk a distance equal to the circumference of the Earth.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 2OQ: The price of gasoline at a particular station is 1.5 euros per liter. An American student can use 33...
icon
Related questions
Question
100%
Just wanted to check if my answers are correct :) please let me know if I’ve made any mistakes.
1. Estimate the number of steps you would have to take to walk a distance equal to the
circumference of the Earth.
The circumference of Earth is approx. 40,075 km. The average step length for an adult
is approx. 0.75 meters (2.5 feet). We divide the distance by the step length:
40,075,000 meters / 0.75 meters/step = 53,433,333 steps
Answer: 1, 53,433,333 steps is needed if we take 2.5 feet per step.
2. Treat a cell in a human as a sphere of radius 1.0 μm.
(a) Determine the volume of a cell - 4.189 x 10^-18 m^3
(b) Estimate the volume of your body - approx. 66 x 10^-3 m^3
(c) Estimate the number of cells in your body - 1.569 x 10^14 cells is the estimated
cells in the body.
Transcribed Image Text:1. Estimate the number of steps you would have to take to walk a distance equal to the circumference of the Earth. The circumference of Earth is approx. 40,075 km. The average step length for an adult is approx. 0.75 meters (2.5 feet). We divide the distance by the step length: 40,075,000 meters / 0.75 meters/step = 53,433,333 steps Answer: 1, 53,433,333 steps is needed if we take 2.5 feet per step. 2. Treat a cell in a human as a sphere of radius 1.0 μm. (a) Determine the volume of a cell - 4.189 x 10^-18 m^3 (b) Estimate the volume of your body - approx. 66 x 10^-3 m^3 (c) Estimate the number of cells in your body - 1.569 x 10^14 cells is the estimated cells in the body.
ed States)
HW. 1.8
Dimensional Analysis
1. Each of the following equations was given by a student during an examination
(a) 1/2mv² = 1/2mv² + √mgh
(b) v = v₁ + at²
(c) ma = 22
Do a dimensional analysis of each equation and explain why the equation can't be correct.
(Hint: Determine the dimensions on each side of the equation and compare them.)
a) Dimension of mv^2/2=M[LT^-1]^2=[ML^2T^-2]
Similarly dimension of mv0^2/2=[ML^2T^-2]
Homework Assignment #1
PH-270-IS1-Spring-2023
Dimension of √(mgh)=[MLT^-2L1^1/2=[M^1/2LT^-1]
Therefore, dimensions on each side are not same.
b) v=v0+at^2
Dimension of v & VO is [LT^-1]
Dimension of at^2 is [LT^-1T^2]=[L]
Therefore dimensions on each side are not same.
c) dimension of ma is [MLT^-2]
Dimension of v^2 is [LT^-1]^2=[[L^2T^-2]
HW1.6
Focus
Transcribed Image Text:ed States) HW. 1.8 Dimensional Analysis 1. Each of the following equations was given by a student during an examination (a) 1/2mv² = 1/2mv² + √mgh (b) v = v₁ + at² (c) ma = 22 Do a dimensional analysis of each equation and explain why the equation can't be correct. (Hint: Determine the dimensions on each side of the equation and compare them.) a) Dimension of mv^2/2=M[LT^-1]^2=[ML^2T^-2] Similarly dimension of mv0^2/2=[ML^2T^-2] Homework Assignment #1 PH-270-IS1-Spring-2023 Dimension of √(mgh)=[MLT^-2L1^1/2=[M^1/2LT^-1] Therefore, dimensions on each side are not same. b) v=v0+at^2 Dimension of v & VO is [LT^-1] Dimension of at^2 is [LT^-1T^2]=[L] Therefore dimensions on each side are not same. c) dimension of ma is [MLT^-2] Dimension of v^2 is [LT^-1]^2=[[L^2T^-2] HW1.6 Focus
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

Blurred answer
Knowledge Booster
Unit conversion
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Inquiry into Physics
Inquiry into Physics
Physics
ISBN:
9781337515863
Author:
Ostdiek
Publisher:
Cengage
Horizons: Exploring the Universe (MindTap Course …
Horizons: Exploring the Universe (MindTap Course …
Physics
ISBN:
9781305960961
Author:
Michael A. Seeds, Dana Backman
Publisher:
Cengage Learning
Astronomy
Astronomy
Physics
ISBN:
9781938168284
Author:
Andrew Fraknoi; David Morrison; Sidney C. Wolff
Publisher:
OpenStax
University Physics Volume 1
University Physics Volume 1
Physics
ISBN:
9781938168277
Author:
William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:
OpenStax - Rice University
College Physics
College Physics
Physics
ISBN:
9781938168000
Author:
Paul Peter Urone, Roger Hinrichs
Publisher:
OpenStax College