et ƒ be the function defined by f (æ) = *+1 with domain [0, 0). The function f has no absolute maximum on its domain. Why does this not contradict the Extreme Value Theorem? The domain of f is not an open interval. B The domain of f is not a closed and bounded interval. The function f is not continuous on its domain. The function f is not differentiable on its domain.

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
Problem 98E: Determine if the statemment is true or false. If the statement is false, then correct it and make it...
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x²+1
Let f be the function defined by f (x)
with domain (0, ∞). The function f has no absolute maximum on its domain. Why does this not contradict the Extreme Value Theorem?
x+1
A
The domain of f is not an open interval.
В
The domain of f is not a closed and bounded interval.
The function f is not continuous on its domain.
The function f is not differentiable on its domain.
Transcribed Image Text:x²+1 Let f be the function defined by f (x) with domain (0, ∞). The function f has no absolute maximum on its domain. Why does this not contradict the Extreme Value Theorem? x+1 A The domain of f is not an open interval. В The domain of f is not a closed and bounded interval. The function f is not continuous on its domain. The function f is not differentiable on its domain.
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