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- Find the Indicated Limit Limh-0(4h5-20h2+2h+1)The limit of (xy-2y) / (x2+y2-4x+4) as (x,y) approaches (2,0) is solved and found out that it does not exist. Can we make this continuous by defining f(2,0) = k for some real value k? If yes, what could this value be? If no, why not?Solve for A and B so that F(x) has a limit at both x=2 and x=4
- 9. Given that limx→3 f(x) = 2 and limx→3 g(x) = −5 compute the following limits:(a) limx→32f(x) = (b) limx→3f(x) − 4g(x) = (c) limx→3g(x) + 3−2 + 3f(x) =Compute the limit (x,y)→(0,0) of 8xy / 2x^2+ 4y^2 along the following paths. (a) Along the y-axis. (b) Along the line y=3x. (c) What can you conclude about the limit?how did you get y^2-4xy to y-4x when there are three y's on top I input the numbers and got 0 which would make it where the limit does not exist.
- How do you evaluate the limit as t approaches 0 (1/t*the square root of 1 + t - 1/t) with the solution -1/2?What is the long term behavior of your hand drawn solution; that is, what is lim t-> infinity M(t) equal to?Solve for (A, B) so that f has a limit at both x=2 and x=4. f(x)=3x+4 for x>=4 f(x)=Ax+B for 2<x<4 f(x)=-2x+3 for x<=2
- Show that the function f(x,y)=8x^2 y subject to 3x−y=9 does not have an absolute minimum or maximum. (Hint: Solve the constraint for y and substitute into f.) Solve the constraint for y. y = ? Substitute into f. f(x,y)= ? Determine the behavior of f as x approaches −∞. limx→−∞f(x,y)= ? Determine the behavior of f as x approaches ∞. limx→∞f(x,y)= ? Does this show that f does not have an absolute maximum or minimum? 1. No 2. YesFor ∑ 1/(n - π) and ∑ (n - 1)/(n3 + 1), solve with either big Θ or with Limit Comparison.1. Broadly speaking, what are the Limit Laws, and why do they help us calculate limits?2. In Example 3, there is a step where the function x2 − 1x − 1is changed to x+ 1. But unlike the secondfunction, the first function is undefined at x = 1. How can we justify changing functions this way?3. Explain the flaw in the following calculation:limx→0x2sin(1/x) = (limx→0x2) · (limx→0sin(1/x)) = 0 · (limx→0sin(1/x)) = 0.