Evaluate the integral 1 2 s s хе dx dy -1

Q: Evaluate double integral.

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Q: Evaluate the iterated integral. (5x + 6y) dx dy 8

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Q: Evaluate the iterated integral. 5 4 (3x + 5y) dx dy 5 4 (3х + 5у) dx dy %3 i

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Q: Evaluate the double integral : 2 e2y+a dy dx

A: In double intregation, first evaluate with dy and then evaluate integral with respect to dx

Q: Evaluate the integral 2 ху S S xe dx dy 0 1

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Q: Evaluate the iterated integral. 2 1T 2 - 2y3) dx dy

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Q: 2 dy dx Evaluate the integral: 1+Vx? +,

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Q: Evaluate the iterated integral. 1. 7zeX dy dx dz - 0/

A: According to limit, first we integrate with respect to y then put x7 = t then solve it.

Q: Evaluate the iterated integral: 2 sin(xy) dy dx п/2 1

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Q: Evaluate the iterated integral. 8. 1 6ze dy dx dz 0/

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Q: Evaluate the iterated integral. 9. (8x – 2y) dy dx 1

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Q: Evaluate the integral: Jo Sí(3xyY+ 5) dy dx Answer:

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Q: 2 The integral J S* 5y dy dx 2

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Q: Evaluate the iterated integral. 4 9. dx dy

A: We need to evaluate the following integral ∫14∫0612x5ydxdy

Q: 1. Evaluate the iterated integral: r12 Jo o cos(2) dy dx. -

A: To find ∫π2π∫0x21xcosyxdydx: First solve ∫0x21xcosyxdy: Let u=yx  dudy=1xdy=xdu…

Q: Evaluate the iterated integral. 8 3 (x + y²) dx dy -1/1

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Q: Calculate the iterated integral. 2 (6 7e* + 3y dx dy

A: From the given problem: I=∫02∫067ex+3ydxdy So, we can also write as: I=∫02∫067ex·e3ydxdy

Q: Evaluate the iterated integral. (3x + 4y3) dx dy

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Q: Evaluate the integral. 36-² 1 [²+² -√36−x² (x² + y²)¹/2 dy dx dz

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Q: Evaluate the following integral. 4 3е ху dz dx dy -111

A: Given: ∫-14∫13∫1ex2yzdz dx dy

Q: Evaluate the double integral 2. dy dx 3/x

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Q: Evaluate the integral S xy dx dy

A: Explanation of the answer is as follows

Q: Compute the integral 1 dx. L (* – i)(x² + 1)

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Q: Evaluate the iterated integral 1 ·1 dy dx (xy + 1)2

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Q: Evaluate the iterated integral.

A: The given integral is ∫01∫0y6x+5y3dxdy

Q: Evaluate the iterated integral 2y dy dx 2 x +1

A: on solving this we get the

Q: Evaluate the integral.

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Q: Evaluate the iterated integral. x³y dy dx 15

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Q: Evaluate the double integral : 9. dy dx 0, 22

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Q: Evaluate the integral. .2 5) t + dx t 1

A: Given,   ∫12t+1t2dx

Q: 22. Compute the given integral. S sin (2x)dx

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Q: So S(x + 3) dy dx 3. Evaluate the double integral:

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Q: Evaluate the integral.

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Q: Evaluate the following integral. 2 5 e 2,2 dz dx dy -221

A: Given: ∫-25∫25∫1ex2y2zdz dx dy ⇒∫1ex2y2zdz=x2y2∫1e1zdz       ...constant out⇒x2y2lnz1e…

Q: iSy dx dy 3.

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Q: Evaluate the integral. S yz dx dz dy 0 2 2 O 128 3

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Q: Evaluate the iterated integral. dy dx -3 9 7 dy dx i -3

A: Double integration

Q: Evaluate the iterated integral. 4 1 (3x – 5y) dy dx -1

A: We need to evaluate the value of the following iterated integral ∫14∫-113x-5ydydx

Q: Evaluate the iterated integral. (3x - 2y) dy dx 1 Jo

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Q: Evaluate the iterated integral. 4 (x2 – 2y²) dx dy

A: Given problem:-

Q: Evaluate the iterated integral. (8x – 2y) dy dx

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Q: Evaluate the iterated integral. '8. 1. 4zel dy dx dz

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Q: Evaluate the integral 1. ( (y - 1)(2y + 1) dy

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Q: Evaluate the iterated integral. (x2 - 8y2) dx dy

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Q: Compute the integral 4x /5 – e2¤ dx. e

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Q: Evaluate the integral I (5х + у) dy dx . 31 1. I = 20 5 2. I 4 27 3. I 20 23 4. I = 20 29 5. I 20

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Q: 2. S*3*+2 dx x+2

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Q: Evaluate the iterated integral. 6. I (8x - 2y) dy dx | 1

A: Given: ∫19∫0x8x-2ydydx

Q: Evaluate the iterated integral. 5 (бх — 10y) dy dx -1 5 (бх — 10у) dy dx%3 i

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Q: Evaluate the iterated integral. 2 4 (x2 – 2y2) dx dy 1 Jo

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