Evaluate the surface integral where S is the part of the cone z = 3 - The surface integral equals 342pi 240 x2 + y2 above the z = 0 plane. √ √ ( x² + y² + 3z² ) dS
Evaluate the surface integral where S is the part of the cone z = 3 - The surface integral equals 342pi 240 x2 + y2 above the z = 0 plane. √ √ ( x² + y² + 3z² ) dS
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 69E
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![Evaluate the surface integral
where S is the part of the cone z = 3-√√x² + y² above the z = 0 plane.
The surface integral equals 342pi
Submit Answer Incorrect. 342 5/30 Previous Tries
1/₂
( x² + y² + 3z² ) ds](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf673b33-84d3-4207-a3d8-77b439e8ab65%2F73cb682a-e50c-45cd-84c6-44e5b968cb52%2Fp9x1vgt_processed.png&w=3840&q=75)
Transcribed Image Text:Evaluate the surface integral
where S is the part of the cone z = 3-√√x² + y² above the z = 0 plane.
The surface integral equals 342pi
Submit Answer Incorrect. 342 5/30 Previous Tries
1/₂
( x² + y² + 3z² ) ds
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