Everest auto industry produces bearing for Mahindra Motor Corporation. The precision of radnis of bearing is very important for its successful functioning. To check the variability in the bearing radius, the company randomly selected ten bearings and measured the radius, the result of which is as shown in the table below. Nominal Nominal radius (cm) #no #no radius (cm) 2.45 2.70 2.65 2.73 2.75 2.64 4. 2.55 2.66 2.76 2.83 a. Calculate the sample standard deviation for the above data. b. Construct a box plot and check whether there is any outlier data in the data distribution. c. Based on the comparisorn between the mean and the quartile, identify the shape of the data distribution. d. Calculate the 55 percentile and interpret the result, e. What is the range of the data distribution? Explain its meaning. 17889
Everest auto industry produces bearing for Mahindra Motor Corporation. The precision of radnis of bearing is very important for its successful functioning. To check the variability in the bearing radius, the company randomly selected ten bearings and measured the radius, the result of which is as shown in the table below. Nominal Nominal radius (cm) #no #no radius (cm) 2.45 2.70 2.65 2.73 2.75 2.64 4. 2.55 2.66 2.76 2.83 a. Calculate the sample standard deviation for the above data. b. Construct a box plot and check whether there is any outlier data in the data distribution. c. Based on the comparisorn between the mean and the quartile, identify the shape of the data distribution. d. Calculate the 55 percentile and interpret the result, e. What is the range of the data distribution? Explain its meaning. 17889
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 22PFA
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Everest auto industry produces bearing for Mahindra Motor Corporation. The precision of radrus
of bearing is very important for its successful functioning. To check the variability in the bearing
radius, the company randomly selected ten bearings and measured the radius, the result of which
is as shown in the table below.
Nominal
radius (cm)
#no
#no
Nominal
radius (cm)
2.45
1.
2.70
6.
71
8.
2.
2.65
2.73
3.
2.75
2.64
4.
2.55
9.
2.66
2.76
10
2.83
a. Calculate the sample standard deviation for the above data.
b. Construct a box plot and check whether there is any outlier data m the data distribution.
c. Based on the comparison between the mean and the quartile, identify the shape of the data
distribution.
d. Calculate the 55 percentile and interpret the result.
e. What is the range of the data distribution? Explain sts meaning.
d States)
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