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Ex.5: Find the equation of the parabola whose focus is (1,-1) and whose directrix is x= -3/2. Solution: the equation of the parabola whose focus is (p,,P;) and its directrix is x=c is (y-k)2 = 4p(x -h) Where k=p, and h=(p1+c)/2 and p=(p1-c)/2 Thus k= -1 and h=(1-(3/2))/2= -1/4 and p (1+3/2)/2 = 5/4 Thus the equation (y + 1)2 = 4

Ex.5: Find the equation of the parabola whose focus is (1,-1) and whose directrix is x= -3/2. Solution: the equation of the parabola whose focus is (p,,P;) and its directrix is x=c is (y-k)2 = 4p(x -h) Where k=p, and h=(p1+c)/2 and p=(p1-c)/2 Thus k= -1 and h=(1-(3/2))/2= -1/4 and p (1+3/2)/2 = 5/4 Thus the equation (y + 1)2 = 4

Algebra and Trigonometry (MindTap Course List)
Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter12: Conic Sections
Section12.CR: Chapter Review
Problem 7CC
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uo 9:10 Asiacell I. CH4-Conic Sections (4-1).pdf 11 jo 10 Ex.5: Find the equation of the parabola whose focus is (1,-1) and whose directrix is x= -3/2. Solution: the equation of the parabola whose focus is (p,,p,) and its directrix is x-c is (y – k)? = 4p(x - h) Where k=p, and h=(p1+c)/2 and p=(p1-c)/2 Thus k = -1 and h=(1-(3/2))/2= -1/4 and p =(1+3/2)/2 = 5/4 Thus the equation (y + 1)2 = 4| x + 1 = y? + 2y = 5x 4 H.W 1: 1. Find the equation of the circle whose center is (3,2) and which passes through the point ( -4, -5). 2. Find the equation of the circle that passes through three points( 0,2), (3,3) and (7,1). 3. find the center and the radius of the circle : 4x2 + 4y2 + 16x – 8y - 5 = 0. H.W2: find the focus and the directrix and the principle axis and the equation of the parabola in standard position that pass through the points (-4,8) and (-4,-8). H.W3: Find the equation of a parabola whose directrix equation is: y + 7= 0 H.W4: Find the equation of the parabola whose focus is (-2,-15/4 ) and whose directrix is y = -17/4.
Transcribed Image Text:uo 9:10 Asiacell I. CH4-Conic Sections (4-1).pdf 11 jo 10 Ex.5: Find the equation of the parabola whose focus is (1,-1) and whose directrix is x= -3/2. Solution: the equation of the parabola whose focus is (p,,p,) and its directrix is x-c is (y – k)? = 4p(x - h) Where k=p, and h=(p1+c)/2 and p=(p1-c)/2 Thus k = -1 and h=(1-(3/2))/2= -1/4 and p =(1+3/2)/2 = 5/4 Thus the equation (y + 1)2 = 4| x + 1 = y? + 2y = 5x 4 H.W 1: 1. Find the equation of the circle whose center is (3,2) and which passes through the point ( -4, -5). 2. Find the equation of the circle that passes through three points( 0,2), (3,3) and (7,1). 3. find the center and the radius of the circle : 4x2 + 4y2 + 16x – 8y - 5 = 0. H.W2: find the focus and the directrix and the principle axis and the equation of the parabola in standard position that pass through the points (-4,8) and (-4,-8). H.W3: Find the equation of a parabola whose directrix equation is: y + 7= 0 H.W4: Find the equation of the parabola whose focus is (-2,-15/4 ) and whose directrix is y = -17/4.
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