Example 11. Calculate the mass of the earth from the following data. Radius of earth R = 6x10° cm = 6 × 10 m. Acceleration due to gravity = 9.8 ms-? Gravitational constant G = 6.67 × 10-!" Nm²/kg². %3D %3D

Example 11. Calculate the mass of the earth from the following data. Radius of earth R = 6x10° cm = 6 × 10 m. Acceleration due to gravity = 9.8 ms-? Gravitational constant G = 6.67 × 10-!" Nm²/kg². %3D %3D

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter13: Universal Gravitation

Section: Chapter Questions

Problem 13.6OQ: An object of mass m is located on the surface of a spherical planet of mass M and radius R. The...

See similar textbooks

Related questions

Q: Question 9 of 36 > Attempt 1 A rack of seven spherical bolwing balls (each 7.10 kg, radius P of 10.9…

Q: 9. Planet A has mass 3M and radius R, while planet B has mas 4M and radius 2R. They are separated by…

A: Let m be the rock’s mass. As the rock is at equal distance from both planets, so, the distance of…

Q: 7. Considering Newton's model of gravity, which of the following statements concerning the…

Q: 93. Gravity If an imaginary line segment is drawn between the centers of the earth and the moon,…

A: The dead spot is calculated as shown below by making F = 0.…

Q: 2-D star cluster puzzle Find the net gravitational force for iv) Hexagon Let m=mass of the star =…

A: find net gravitation force for hexagon

Q: - The density of newly discovered planet is twice that of Earth. The acceleration due to gravity at…

Q: 2) If an object weighs 2500N on earth, what is the weight of the object on a planet - the mass of…

A: Given data: The weight of object on the Earth is WE=2500 N. The mass of planet is m=0.5mE. The…

Q: 8. The earth and the sun (mass 2x1030 kg) are separated by 150 million km, from center to center.…

Q: 2. A researcher determines that the acceleration of gravity at the north and south pole is measured…

A: The given values are, gpoles=9.832 m/s2gequator=9.780 m/s2ME=5.98×1024 kg

Q: 3. The asteroid belt between Mars and Jupiter consists of many fragments (which some space…

A: 3) Simply we can say that the centre of mass is a hypothetical point where entire mass of an object…

Q: How far from Earth must a space probe be along a line toward the Sun so that the Sun's gravitational…

A: Mass of sun = 2× 1030kg Mass of earth = 6×1024kg Distance between Earth and Sun = 1.5×1011

Q: m, m2

A: can expression for the gravitational field of m2:we know:g=Gmr2here r=I2-Iag2=Gm2I2-Ia2

Q: 4) The acceleration due to gravity at the surface of a planet of mass M, radius R, is given by the…

Q: - The density of newly discovered planet is twice that of Earth. The acceleration due to gravity at…

Q: 86. A solid sphere of mass M and a ring of mass m have their centres lying on the x-axis separated…

Q: 1. Consider a space shuttle which has a mass of about 1.0 x 10° kg and circles the Earth at an…

A: 1) mass of space shuttle (m)= 105 kg altitude (h) = 200 km

Q: acceleration

Q: Problem 5. Mr. Spock orbits a spherical planet X with his spaceship. To remain in a circular orbit…

A: this is simple question about orbital speed .

Q: 5. The moon is 3.9 x 10° km from ter and 1.5 x 10 km from the sun's center. If the masses of the…

A: The gravitational force between the two masses is given by F =G m m'r2 where, r is the distance…

Q: What is the gravitational force acting on a 70-kg rock due to an 80-kg rock that is 55 meters away?…

A: Given that, the value of mass m1 and m2 and distance between given rocks and also given value of the…

Q: 6.) A new Earth size planet has been discovered in a distant star system. The planet has six times…

A: The radius and the mass of the new planet in term of the radius and mass of the earth are:

Q: Two objects, with masses m 1 and m 2 ;, are originally a distance r apart. The gravitational force…

Q: You have landed on a strange planet. The computer says its radius is 6.9 x 10 m. You jump, and find…

A: Given : Radius of the planet, R = 6.9*107 m acceleration due to gravity, g = 26.8 m/s2 We…

Q: Calculate the effective value of g, the acceleration of gravity, at 6000 km, above the Earth's…

A: Note: As per the guidelines, we can only answer first question of multiple question. Sorry for the…

Q: What is the gravitational acceleration close to the surface of a planet with a mass of 2 M E and…

A: Given, Mass of the earth =ME The radius of the earth = RE

Q: An object with mass m1 = 42 kg is located at the origin. Another object with mass m2 = 86 kg is…

A: m1 = 42 kg m2 = 86 kg la= 0.035 m lb = 0.105 m

Q: - The density of newly discovered planet is twice that of Earth. The acceleration due to gravity at…

Q: The weight of a person on the earth is 80 kg. What will be his weight on the moon ? Mass of the moon…

Q: Problem 6: Ameteoroid is moving towards a planet. It has mass m = 0.86x10° kg and speed v = 1.1x10'…

A: Express the relation for the potential energy of the meteoroid at distance R1. PE1=-GMmR1 Here, PE1…

Q: ce the gravitational constant to be G = 6.67x10-11N.m²/kg?. press your answer in newtons to three…

A: Given values:- Masses,(m)=m1=m2=m3=8000 kg ----(1) Gravitational constant,(G)=6.67 x 10-11 N-m2/kg2…

Q: 3. The mass of the Earth is approximately 81 times the 5. mass of the Moon. If the Earth exerts a…

Q: 6. The center of the moon and the center of the Earth are 3.80 x 10° km apart. The mass of the moon…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Problem 6: A meteoroid is moving towards a planet. It has mass m = 0.86x10° kg and speed v = 1.1x10'…

Q: 1)How fast do you need to swing a 170-gg ball at the end of a string in a horizontal circle of…

A: Since you have asked multiple questions, we will answer the first question for you according to the…

Q: A sateltle orbits at a height of 6,000 km above the earth’s surface. REarth = 6.38 × 106 m, mEarth =…

A: Given:- hright of the orbits =6000 km mearth =5.98×1024 kg Rearth =6.38×106 m G=6.67×10-11…

Q: Concern the planet Mars, which has a radius of 3400 km. On Mars, the acceleration due to gravity is…

Q: 1). A 650 kg satellite orbits Earth with a speed of 5.3 km/s at a distance of 3.5x 107 m from…

Q: 1. Consider a space shuttle which has a mass of about 1.0 x 10 kg and circles the Earth at an…

A: Given: The mass of the space shuttle is 1x105 kg. The altitude of the object from the earth is 200…

Q: 4) The acceleration due to gravity at the surface of a planet of mass M, radius R, is given by the…

A: Given: Radius of cylinder, R = 300 m The acceleration due to gravity on Earth, g = 9.8 m/s2

Q: 5. The acceleration of gravity on the Moon's surface is known to be about 1/6 the acceleration of…

A: The acceleration due to gravity for a planet is given by: gp=GMr2.......(1)wheregp is the…

Q: uic same height 4. Planet Z-34 has a mass equal to 1/9 that of Earth and a radius equal to 1/3 that…

Q: 4) The acceleration due to gravity at the surface of a planet of mass M, radius R, is given by the…

Q: 8. What is the acceleration due to gravity on the surface of the (a) moon and (b) Mars? The mass of…

A: Mass of moon Mm=7.35×1022 kg Mass of mars MM=6.418×1023 kg Radius of moon Rm=1731.7 km Radius of…

Q: |(II) A mass M is ring shaped with radius r. A small mass m is placed at a distance x along the…

Q: 2) If an object weighs 2500 N on earth, what is the weight of the object on a planet - the mass of…

A: Write the given values with the suitable variables. WE=2500 NM=12MER=6RE Here, WE is the weight on…

Q: The gravitational field is another name for the acceleration due to gravity, depending on position,…

A: Gravitational field near the surface of earth (g) = 9.8 ms2radius of earth (Rearth) = 6400 km height…

Q: The planet Mars has a radius of 3,390 km. The value of g (free fall acceleration) at the surface of…

A: Given Data: The mass of the planet Mars is: R=3390 km=3390×103 m The gravitational acceleration on…

Q: <Homework 11 Exercise 13.19 - Enhanced - with Feedback A planet orbiting a distant star has radius…

A: The acceleration due to gravity at the surface of the planet can be determined as, Here, G, M and R…

Question

Example 11. Calculate the mass of the earth from the following data.
Radius of earth R = 6x10® cm = 6 × 10° m.
Acceleration due to gravity = 9.8 ms-2
Gravitational constant G = 6.67 × 10-lI Nm³/kg².

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Given Data

VIEW

Formula Used

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

(a) Calculate Earth's mass given the acceleration due to gravity at the North Pole is 9.830 m/s2 and the radius of the Earth is 6371 km from center to pole. (b) Compare this with the accepted value of 5.9791024 kg.
Unreasonable Results (a) Based on Kepler's laws and information on the orbital characteristics of the Moon, calculate the orbital radius for an Earth satellite having a period of 1.00 h. (b) What is unreasonable about this result? (c) What is unreasonable or inconsistent about the premise of a 1.00 h orbit?
(a) Given that the period of the Moons orbit about the Earth is 27.32 days and the nearly constant distance between the center of the Earth and the center of the Moon is 3.84 108 m, use Equation 13.11 to calculate the mass of the Earth. (b) Why is the value you calculate a bit too large?
An object of mass m is located on the surface of a spherical planet of mass M and radius R. The escape speed from the planet does not depend on which of the following? (a) M (b) m (c) the density of the planet (d) R (e) the acceleration due to gravity on that planet
The Sun has a mass of approximately 1.99 1030 kg. a. Given that the Earth is on average about 1.50 1011 m from the Sun, what is the magnitude of the Suns gravitational field at this distance? b. Sketch the magnitude of the gravitational field due to the Sun as a function of distance from the Sun. Indicate the Earths position on your graph. Assume the radius of the Sun is 7.00 108 m and begin the graph there. c. Given that the mass of the Earth is 5.97 1024 kg, what is the magnitude of the gravitational force on the Earth due to the Sun?
In Example 2.6, we considered a simple model for a rocket launched from the surface of the Earth. A better expression for the rockets position measured from the center of the Earth is given by y(t)=(R3/2+3g2Rt)2/3j where R is the radius of the Earth (6.38 106 m) and g is the constant acceleration of an object in free fall near the Earths surface (9.81 m/s2). a. Derive expressions for vy(t) and ay(t). b. Plot y(t), vy(t), and ay(t). (A spreadsheet program would be helpful.) c. When will the rocket be at y=4R? d. What are vy and ay when y=4R?
The mass of the Earth is approximately 5.98 1024 kg, and the mass of the Moon is approximately 7.35 1022 kg. The Moon and the Earth are separated by about 3.84 108 m. a. What is the magnitude of the gravitational force that the Moon exerts on the Earth? b. If Serena is on the Moon and her mass is 25 kg, what is the magnitude of the gravitational force on Serena due to the Moon? The radius of the Moon is approximately 1.74 106 m.
Suppose the gravitational acceleration at the surface of a certain moon A of Jupiter is 2 m/s2. Moon B has twice the mass and twice the radius of moon A. What is the gravitational acceleration at its surface? Neglect the gravitational acceleration due to Jupiter. (a) 8 m/s2 (b) 4 m/s2 (c) 2 m/s2 (d) 1 m/s2 (e) 0.5 m/s2
The mass of a planet is one third that of the earth and the diameter of the planet is six times that of the earth. What is the acceleration due to gravity on the surface of the planet? Given g on earth is 9.8 ms-2.
A 10 kg object sits on the earth’s surface. What is the force of gravity between the object andthe earth? (mass of the earth = 5.97 x 1024 kg, radius of the earth = 6.37 x 106 m)
9.) Mars has a mass of 6.39 × 1023 kg and radius 3.39 × 106 m. What is the magnitude of the gravitational acceleration g on Mars' surface, in m/s2? Use G = 6.67 × 10-11 N·m2/kg2. Your answer needs to have 3 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.
At a given point above Earth's surface, the acceleration due to gravity is 65 m/s². What is the altitude of this point from the center of Earth. Answer in terms of Earth's radius . A. 0.66 R B. 1.0 R C. 1.23 R D. 1.5 R