Example: 2.7 A hollow circular nylon pipe (see Fig 1-23) supports a load P = 7800 N, which is uniformly distributed around a cap plate at the top of the lower pipe. A second load Pg is applied at the bottom. The inner and outer diameters of the upper and lower parts of the pipe are d, = 51 mm, d, = 60 mm, d, = 57 mm, and d = 63 mm, respectively. The upper pipe has a length L,= 350 mm; the lower pipe length is L2 = 400 mm. Neglect the self-weight of the pipes. (a) Find Pg so that the tensile stress in upper part is 14.5 MPa. What is the resulting stress in the lower part? (b) If P, remains unchanged, find the new value of P, so that upper and lower parts have same tensile stress.

Example: 2.7 A hollow circular nylon pipe (see Fig 1-23) supports a load P = 7800 N, which is uniformly distributed around a cap plate at the top of the lower pipe. A second load Pg is applied at the bottom. The inner and outer diameters of the upper and lower parts of the pipe are d, = 51 mm, d, = 60 mm, d, = 57 mm, and d = 63 mm, respectively. The upper pipe has a length L,= 350 mm; the lower pipe length is L2 = 400 mm. Neglect the self-weight of the pipes. (a) Find Pg so that the tensile stress in upper part is 14.5 MPa. What is the resulting stress in the lower part? (b) If P, remains unchanged, find the new value of P, so that upper and lower parts have same tensile stress.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter2: Axially Loaded Members

Section: Chapter Questions

Problem 2.4.14P: A hollow circular pipe (see figure} support s a load P that is uniformly distributed around a cap...

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