Example 24.31. Determine the ultimate net bearing capacity of the circular footing shown in Fig. 24.33. Also, compute the change in ultimate net bearing capacity, if the entire region is flooded, due 10 which the ground water level reaches ground level. 1.5 m 2m Clay Cu = 48 kPa 3.5 m $=0° Y 1.8 g/cc No = 5.7 W.T.

Example 24.31. Determine the ultimate net bearing capacity of the circular footing shown in Fig. 24.33. Also, compute the change in ultimate net bearing capacity, if the entire region is flooded, due 10 which the ground water level reaches ground level. 1.5 m 2m Clay Cu = 48 kPa 3.5 m $=0° Y 1.8 g/cc No = 5.7 W.T.

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter6: Shallow Foundations: Ultimate Bearing Capacity

Section: Chapter Questions

Problem 6.14P: A 2 m 3 m spread footing placed at a depth of 2 m carries a vertical load of 3000 kN and a moment...

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