Example 3.15: A fluid at 4.15 bar is expanded reversibly according to a law PV = constant to a pressure of 1.15 bar until it has a specific %3D volume of 0.12 m3/kg. It is then cooled reversibly at a constant pressure, then is cooled at constant volume until the pressure is 0.62 bar; and is then allowed to compress reversibly according to a law PVn = constant back to the initial conditions. The work done in the constant pressure is 0.525 kJ, and the mass of fluid present is 0.22 kg. Calculate the value of (n) in the fourth process, the net-work of the cycle and sketch the cycle on a P-V diagram.Answer: n=1.3182, network 0.9076 kJ

Example 3.15: A fluid at 4.15 bar is expanded reversibly according to a law PV = constant to a pressure of 1.15 bar until it has a specific %3D volume of 0.12 m3/kg. It is then cooled reversibly at a constant pressure, then is cooled at constant volume until the pressure is 0.62 bar; and is then allowed to compress reversibly according to a law PVn = constant back to the initial conditions. The work done in the constant pressure is 0.525 kJ, and the mass of fluid present is 0.22 kg. Calculate the value of (n) in the fourth process, the net-work of the cycle and sketch the cycle on a P-V diagram.Answer: n=1.3182, network 0.9076 kJ

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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