Example 4-10: A joint discrete probability function f(r, y) is expressed below. Find P(z+yS1). KL 3. for z = 0,1,2; y= 0,1,2; and 0SI+yS2 f(1. y) = elsewhere Solution: First we construct the table for the joint discrete probability distribution. f(2, y) 0. 3/28 9/28 3/28 1 3/14 3/14 2. 1/28 Then: How find Table in the slotion ?!

A First Course in Probability (10th Edition)
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ISBN:9780134753119
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Chapter1: Combinatorial Analysis
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I need answer within 20 minutes please please with my best wishes
= 0.08 + 0.28 +0.04 = 0.4
Example 4-10: A joint discrete probability function f(x.y) is expressed below. Find
P(z +yS1). t
2-I
for a = 0, 1, 2; y = 0,1,2; and 0SI+yS2
f(1, y) =
elsewhere
Solution: First we construct the table for the joint discrete probability distribution.
f(z, y)
2
9/28
3/14
3/28
3/28
1
3/14
2.
1/28
0.
Then:
How find Table in the
slotion ?!
Transcribed Image Text:= 0.08 + 0.28 +0.04 = 0.4 Example 4-10: A joint discrete probability function f(x.y) is expressed below. Find P(z +yS1). t 2-I for a = 0, 1, 2; y = 0,1,2; and 0SI+yS2 f(1, y) = elsewhere Solution: First we construct the table for the joint discrete probability distribution. f(z, y) 2 9/28 3/14 3/28 3/28 1 3/14 2. 1/28 0. Then: How find Table in the slotion ?!
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