EXAMPLE 4 Investigate the following limit. lim sin SOLUTION Again the function f(x) = sin(57/x) is undefined at 0. Evaluating the function for some small values of x, we get f(1) = sin 5n = 0 () = sin 10n = 0 = sin 157 =0 = sin 20 TT = 0 f(0.1) = sin 50n = 0 f(0.01) = sin 500n = 0 Similarly, f(0.001) = f(0.0001) = 0. On the basis of this information we might be tempted to guess that lim sin 5n = 0 but this time our guess is wrong. Note that although f(1/n) = sin 5nm = X for any integer n, it is also true that f(x) = 1 for infinitely many values of x that approach 0. You can see this from the graph of f given in the figure. The compressed lines near the y-axis indicate that the values of f(x) oscillate between 1 and -1 infinitely often as x approaches 0. (Use a graphing device to graph f(x) and zoom in toward the origin several times. What do you observe?) Since the values of f(x) do not approach a fixed number as x approaches 0, lim sin does not exist.

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ISBN:9781337111348
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Chapter1: Functions
Section1.2: Functions Given By Tables
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EXAMPLE 4
Investigate the following limit.
lim sin
SOLUTION
Again the function f(x) = sin(5t/x) is undefined at 0. Evaluating the function for some small values of x, we get
()
()
f(1)
= sin 5n =0
= sin 10n = 0
= sin 15n = 0
= sin 20
TT = 0
f(0.1) = sin 50n = 0
f(0.01) = sin 500n = 0
Similarly, f(0.001) = f(0.0001) = 0. On the basis of this information we might be tempted to guess that
lim sin
but this time our guess is wrong. Note that although f(1/n) = sin 5m =
infinitely many values of x that approach 0. You can see this from the graph of f given in the figure. The compressed lines near the y-axis
indicate that the values of f(x) oscillate between 1 and –1 infinitely often as x approaches 0. (Use a graphing device to graph f(x) and
zoom in toward the origin several times. What do you observe?) Since the values of f(x) do not approach a fixed number as x approaches
0,
for any integer n, it is also true that f(x) = 1 for
lim sin
does not exist.
Transcribed Image Text:EXAMPLE 4 Investigate the following limit. lim sin SOLUTION Again the function f(x) = sin(5t/x) is undefined at 0. Evaluating the function for some small values of x, we get () () f(1) = sin 5n =0 = sin 10n = 0 = sin 15n = 0 = sin 20 TT = 0 f(0.1) = sin 50n = 0 f(0.01) = sin 500n = 0 Similarly, f(0.001) = f(0.0001) = 0. On the basis of this information we might be tempted to guess that lim sin but this time our guess is wrong. Note that although f(1/n) = sin 5m = infinitely many values of x that approach 0. You can see this from the graph of f given in the figure. The compressed lines near the y-axis indicate that the values of f(x) oscillate between 1 and –1 infinitely often as x approaches 0. (Use a graphing device to graph f(x) and zoom in toward the origin several times. What do you observe?) Since the values of f(x) do not approach a fixed number as x approaches 0, for any integer n, it is also true that f(x) = 1 for lim sin does not exist.
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