EXAMPLE 4 The radius of a sphere was measured and found to be 23 cm with a possible error in measurement of at most 0.02 cm. What is the maximum error in using this value of the radius to compute the volume of the sphere? SOLUTION If the radius of the sphere is r then its volume is V = ar. If the error in the measured value of r is denoted by dr = Ar, then the %3D corresponding error in the calculated value of V is AV, which can be approximated by the differential dV = 4xr dr. When r= 23 and dr = 0.02, this becomes dV = 4x( (round to the nearest integer). The maximum error in the calculated volume is about cm3.
EXAMPLE 4 The radius of a sphere was measured and found to be 23 cm with a possible error in measurement of at most 0.02 cm. What is the maximum error in using this value of the radius to compute the volume of the sphere? SOLUTION If the radius of the sphere is r then its volume is V = ar. If the error in the measured value of r is denoted by dr = Ar, then the %3D corresponding error in the calculated value of V is AV, which can be approximated by the differential dV = 4xr dr. When r= 23 and dr = 0.02, this becomes dV = 4x( (round to the nearest integer). The maximum error in the calculated volume is about cm3.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 67E
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