SchlumbergerGeneralEquivalent NaCl Salinity of SaltsGen-4(former Gen-8)GenLi (2.5)*2.0OH (5.5)*2.0E NH, (1.9)*Mg1.5KСаCO,Na and CI (1.0)1.01.0KMultiplierSO,СаCO,0.5 E NO, (0.55)"Br (0.44)*HCO,so,E I (0.28)*HCO,Mg-0.51020501002005001,000 2,0005,000 10,000 20,000 50,000 100,000300,000Total solids concentration (ppm or mg/kg)1 Multipliers that do not vary appreciably for low concentrations(less than about 10,000 ppm) are shown at the left margin of the chart© Schlumberger Example 5.2: - Formation water sample with solids concentrations of calcium(Ca) == 460 ppm, sulfate (SO4) = 1,400 ppm, and Na plus Cl = 19,000 ppm.%3DFind Equivalent NaCl solution in ppm.

The values and figure given in the question are as follows: The concentration of Ca=460 ppm The…

Answered: Example 5.2: - Formation water sample…

Example 5.2: - Formation water sample with solids concentrations of calcium (Ca) = 460 ppm, sulfate (SO4) = 1,400 ppm, and Na plus Cl = 19,000 ppm. Find Equivalent NaCl solution in ppm.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter9: In Situ Stresses

Section: Chapter Questions

Problem 9.11P

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Concept explainers

Laboratory Determination of Hydraulic Conductivity

Hydraulic conductivity is the measure of flowability of water inside the soil in the presence of a hydraulic gradient. The hydraulic gradient is defined as the difference in the water heads in the soil, which induces a water motion. In simple terms, a hydraulic gradient is the presence of a potential that induces a flow of water.

Question

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Schlumberger
General
Equivalent NaCl Salinity of Salts
Gen-4
(former Gen-8)
Gen
Li (2.5)*
2.0
OH (5.5)*
2.0
E NH, (1.9)*
Mg
1.5
K
Са
CO,
Na and CI (1.0)
1.0
1.0
K
Multiplier
SO,
Са
CO,
0.5 E NO, (0.55)"
Br (0.44)*
HCO,
so,
E I (0.28)*
HCO,
Mg
-0.5
10
20
50
100
200
500
1,000 2,000
5,000 10,000 20,000 50,000 100,000
300,000
Total solids concentration (ppm or mg/kg)
1 Multipliers that do not vary appreciably for low concentrations
(less than about 10,000 ppm) are shown at the left margin of the chart
© Schlumberger

Example 5.2: - Formation water sample with solids concentrations of calcium
(Ca) =
= 460 ppm, sulfate (SO4) = 1,400 ppm, and Na plus Cl = 19,000 ppm.
%3D
Find Equivalent NaCl solution in ppm.

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