Example : Figure shows bellow a drilled shaft without a bell Assume the folowing values : L1 =6 m Cu(1) = 50 KN/m L2 = 7 m Cu2) = 75 KN/m? Ds = 1.5m Determine : The net ultimate point bearing capacity by use general equation. b. The ultimate skin friction by use general equation. The working load, Qw, factor of safety = 3 a. C.

Example : Figure shows bellow a drilled shaft without a bell Assume the folowing values : L1 =6 m Cu(1) = 50 KN/m L2 = 7 m Cu2) = 75 KN/m? Ds = 1.5m Determine : The net ultimate point bearing capacity by use general equation. b. The ultimate skin friction by use general equation. The working load, Qw, factor of safety = 3 a. C.

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter10: Drilled-shaft Foundations

Section: Chapter Questions

Problem 10.7P

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