Example : For the following traffic compositionPassenger carBusses (>25 passenger) =5%Heavy vehiclemotorcycleDetermine the equivalent passenger car unit if the total number ofvehicles passing is 8500 veh.=50%=42%=3%Solution:No. Passenger carsNo. of busses (25 passenger)No. heavy vehicleNo. of motorcycleTotal equivalent passenger car == 8500* (50/100) = 4250= 8500* (05/100) = 425= 8500* (42/100) = 4570= 8500* (03/100) = 2554250*1+ 425*2.5+3570*3+255*0.33Total equivalent passenger car =4250+1062.5+10710+84.15 = 16107 PCUActivate WindowsGo to Settings to activate

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Example : For the following traffic composition Passenger car Busses (>25 passenger) Heavy vehicle motorcycle Determine the equivalent passenger car unit if the total number of vehicles passing is 8500 veh. =50% =5% =42% =3% Solution: No. Passenger cars No. of busses (25 passenger) = 8500* (05/100) = 425 No. heavy vehicle No. of motorcycle Total equivalent passenger car = = 8500* (50/100) = 4250 %3D = 8500* (42/100) = 4570 = 8500* (03/100) = 255 %3D 4250*1+ 425*2.5+3570*3+255*0.33 Total equivalent passenger car = 4250+1062.5+10710+84.15 = 16107 PCU %3D Activate Wind Go to Settings to

Example : For the following traffic composition Passenger car Busses (>25 passenger) Heavy vehicle motorcycle Determine the equivalent passenger car unit if the total number of vehicles passing is 8500 veh. =50% =5% =42% =3% Solution: No. Passenger cars No. of busses (25 passenger) = 8500* (05/100) = 425 No. heavy vehicle No. of motorcycle Total equivalent passenger car = = 8500* (50/100) = 4250 %3D = 8500* (42/100) = 4570 = 8500* (03/100) = 255 %3D 42501+ 4252.5+35703+2550.33 Total equivalent passenger car = 4250+1062.5+10710+84.15 = 16107 PCU %3D Activate Wind Go to Settings to

Traffic and Highway Engineering

5th Edition

ISBN:9781305156241

Author:Garber, Nicholas J.

Publisher:Garber, Nicholas J.

Chapter13: Evaluating Transportation Alternatives

Section: Chapter Questions

Problem 4P

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Similar questions

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