Example Stranded conductor 27/2.9 mm. calculate the equivalent diameter of conductor. Solution: The diameter of one strand (d) = 2.9 mm No. of stranded in conductor (Ns)=27 Therefore for No. of layer = 2, distributed as follow: = [1 + 6+ core 12] 1st layer 2nd layer

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter4: Transmission Line Parameters
Section: Chapter Questions
Problem 4.4P: One thousand circular mils or 1 kcmil is sometimes designated by the abbreviation MCM75C. Data for...
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N==27
Example
Stranded conductor 27/2.9 mm. calculate the equivalent diameter of conductor.
Solution:
The diameter of one strand (d) = 2.9 mm No. of stranded in conductor (Ns) = 27 Therefore for No.
of layer = 2, distributed as follow: = [1 +
6+
core
1st layer
12]
2nd layer
Transcribed Image Text:Example Stranded conductor 27/2.9 mm. calculate the equivalent diameter of conductor. Solution: The diameter of one strand (d) = 2.9 mm No. of stranded in conductor (Ns) = 27 Therefore for No. of layer = 2, distributed as follow: = [1 + 6+ core 1st layer 12] 2nd layer
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