Excercise 40 Prove that the pairwise radical axes of three circles with not collinear centers meet a сотmon point. Hint. Equalities O,p² – rỉ = 02P² – rž and O2P² – r = O3P2 – r? - imply that O1P² – rỉ = O3P² – rž, i.e. the intersection point of the radical axes l12 and l23 is on l13 as well. It is called the radical center of the circles.
Excercise 40 Prove that the pairwise radical axes of three circles with not collinear centers meet a сотmon point. Hint. Equalities O,p² – rỉ = 02P² – rž and O2P² – r = O3P2 – r? - imply that O1P² – rỉ = O3P² – rž, i.e. the intersection point of the radical axes l12 and l23 is on l13 as well. It is called the radical center of the circles.
Elementary Geometry for College Students
6th Edition
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Daniel C. Alexander, Geralyn M. Koeberlein
Chapter10: Analytic Geometry
Section10.4: Analytic Proofs
Problem 28E
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Let A,B and C be three circles with no collinear centers.
Let be the intersection point and be the radical axis of circles A and B.
Let be the intersection point and be the radical axis of circles B and C
Let be the intersection point and be the radical axis of circles C and A.
Let be the centers of the three circles.
Let P be a point, then the radical axis of circles A and B is defined as the line along which the tangents to those circles are equal in length.
Similarly, the tangents to circles B and C must be equal in length on their radical axis.
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