EXERCISE 7: Sequence: The first term of a sequence is a1 = sin(1). The next terms are: a2 = min{a1,sin(2)} (the smallest of a1 and sin 2), az = min{a2, sin(3)} (the smallest of az and sin 3),... an+1 = min{an, sin(n + 1)} (the smallest of an and sin(n +1)). Is this sequence {an} converging or diverging?
EXERCISE 7: Sequence: The first term of a sequence is a1 = sin(1). The next terms are: a2 = min{a1,sin(2)} (the smallest of a1 and sin 2), az = min{a2, sin(3)} (the smallest of az and sin 3),... an+1 = min{an, sin(n + 1)} (the smallest of an and sin(n +1)). Is this sequence {an} converging or diverging?
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 2RE
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![EXERCISE 7: Sequence: The first term of a sequence is a1 = sin(1). The next terms are:
a2 = min{a1,sin(2)} (the smallest of a1 and sin 2),
az = min{a2, sin(3)} (the smallest of az and sin 3),...
an+1 = min{an, sin(n + 1)} (the smallest of an and sin(n +1)).
Is this sequence {an} converging or diverging?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe1358fe4-d6b6-4b51-b146-50dcd609f324%2F7e736ce1-3b02-4590-8de0-48ad76c8c6d1%2Fp1ioe.png&w=3840&q=75)
Transcribed Image Text:EXERCISE 7: Sequence: The first term of a sequence is a1 = sin(1). The next terms are:
a2 = min{a1,sin(2)} (the smallest of a1 and sin 2),
az = min{a2, sin(3)} (the smallest of az and sin 3),...
an+1 = min{an, sin(n + 1)} (the smallest of an and sin(n +1)).
Is this sequence {an} converging or diverging?
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