Exercise 8:[Hard] Let f be a function differentiable on (c-p, c+p) for some p > 0. Suppose f has a maximum at c, ie., f(c)2 f(x) for all x € (c - p,c+ p) Last modified: October 29, 2019, Due: November 6, 2019. 1 ΜΑΤΗ 15100, SECTION 13 2 (a) Prove that f'(c) < 0. f(c+h)-f(c) Hint: Consider the limit: lim0+ What can be said about the numerator? (b) Prove that f'(c) > 0. f(c+h)-f(c) Hint: Consider the limit: lim/0- (c) Conclude that f'(c) = 0. Remark: The same result is true for minima as well, with basically the same proof. Note this is not an if and only if statement: let g(x) = x3. Then g'(0) = 0, but g has neither a maximum nor minimum at x = 0
![Exercise 8:[Hard] Let f be a function differentiable on (c-p, c+p) for some p > 0. Suppose f has a maximum
at c, ie., f(c)2 f(x) for all x € (c - p,c+ p)
Last modified: October 29, 2019, Due: November 6, 2019.
1
ΜΑΤΗ 15100, SECTION 13
2
(a) Prove that f'(c) < 0.
f(c+h)-f(c)
Hint: Consider the limit: lim0+
What can be said about the numerator?
(b) Prove that f'(c) > 0.
f(c+h)-f(c)
Hint: Consider the limit: lim/0-
(c) Conclude that f'(c) = 0.
Remark: The same result is true for minima as well, with basically the same proof.
Note this is not an if and only if statement: let g(x) = x3. Then g'(0) = 0, but g has neither a
maximum nor minimum at x = 0](https://prod-qna-question-images.s3.amazonaws.com/qna-images/question/f121ba60-7058-4a7c-893c-99f8ff2d6afa/cc9711ae-becf-4287-9349-e07f6f3ca987/efmrv3c.png)
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Exercise 8:[Hard] Let f be a function differentiable on (c-p, c+p) for some p > 0. Suppose f has a maximum at c, ie., f(c)2 f(x) for all x € (c - p,c+ p) Last modified: October 29, 2019, Due: November 6, 2019. 1 ΜΑΤΗ 15100, SECTION 13 2 (a) Prove that f'(c) < 0. f(c+h)-f(c) Hint: Consider the limit: lim0+ What can be said about the numerator? (b) Prove that f'(c) > 0. f(c+h)-f(c) Hint: Consider the limit: lim/0- (c) Conclude that f'(c) = 0. Remark: The same result is true for minima as well, with basically the same proof. Note this is not an if and only if statement: let g(x) = x3. Then g'(0) = 0, but g has neither a maximum nor minimum at x = 0
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