Exercise#6: The current through a 250-mH inductor takes the following values. Calculatethe expression for the voltage across the inductor in each case.a. i (t) = 5 sin 25t Ab. i̟(t) :c. i (t) = 25 cos(100t + TT/3) Ad. i (t) = 20 sin(10t – /12) A=-10 cos 50t A

The relation between the voltage and current is as follows for the inductor V = L di/dt L = inductor…

Answered: Exercise#6: The current through a…

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter18: Resistive-inductive Parallel Circuits

Section: Chapter Questions

Problem 2PP: Assume that the current flow through the resistor, IR, is 15 A; the current flow through the...

See similar textbooks

Similar questions

Assume that the current flow through the resistor, IR, is 15 A; the current flow through the inductor, IL is 36 A; and the circuit has an apparent power of 10,803 VA. The frequency of the AC voltage is 60 Hz. ET ER EL IT IR15A IL36A Z R XL VA10,803 P VARSL PF L
A 0.010 H inductor is connected to a voltage source whose expression is e=311sin (377t+ pi/2) V. Write the expression for current.
* If the current through a 5 mH inductor is increasing at 3 A/s, what is the voltage across the inductor? * The current in an 8 µH inductor is given by i(t) = 3t + 2 A. What is the value of the inductors voltage at t = 2 s.
Two capacitors, of capacitance 3µF and 5µF, are connected as shown to batteries A and B which have EMF 4 V and 12 V respectively. What is the energy stored in each of the capacitors? Calculate also the stored energy in each capacitor when the terminals of battery A are reversed, and when the battery B is disconnected, and the points X and Y are connected together.
A resistance of 10 ohm, an inductor of 300 mH and a capacitor of 50 uF are connected in series. If the AC voltage supplied to the connection is given by v = 300 sin (2 π 50 t + 30), write the equation for the current.
Find the equivalent capacitance of given circuit between the point A and B) if the applied voltage across A-B, equal =5 VRMS , 1000 Hz. Note: Take the capacitance of each capacitor as C=680µF)
The current in a 100-mH inductor is i(t) = 2 sin377t A. Find a) the voltage across the inductor andb) the expression for the energy stored in the element.
Two capacitors are in parallel with a voltage source of 15 V. If the capacitors are rated at 10 μF and 5 μF respectively, calculate: Equivalent capacitance V1 and V2 Equivalent charge, Q1 , and Q2
The current through a 0.5-H inductor is given byiL = 2 cos(377t + π/6).Write the expression for thevoltage across the inductor.
A resistance of 100 Ω, an inductance of 0.1 H, and a capacitance of 5(10−5) F are connected in series.If the total electromotive force is given by 110 sin 377t, such that at t = 0,Q = 0, and i = 0, find thecurrent for t > 0.
Can you please help with this question? The triangular voltage pulse shown below is applied to a 200 mF capacitor. a) Write the expressions thatdescribe vc(t) in the five time intervals t < 0, 0 ≤ t ≤ 2 , 2 ≤ t ≤ 6, 6 ≤ t ≤ 8, and t > 8. b) Derive theexpressions for the capacitor current, power, and energy for the time intervals in part (a).
1. Calculate the capacitance between two parallel plates, each of which is 100 sq. Inches and 2 mm apart in air. 2. A capacitor is charged with 0.23 J of energy at a voltage of 48V. What is its capacitance? 3. A 50-uF capacitor is initially charged. Determine the initial charge of the 50-uF capacitor if the charge transferred to a 100-uF capacitor, when connected in parallel, is 200-uC.

SEE MORE QUESTIONS

Recommended textbooks for you

Delmar's Standard Textbook Of Electricity

Electrical Engineering

ISBN:

9781337900348

Author:

Stephen L. Herman

Publisher:

Cengage Learning

Delmar's Standard Textbook Of Electricity

Electrical Engineering

ISBN:

9781337900348

Author:

Stephen L. Herman

Publisher:

Cengage Learning

SEE MORE TEXTBOOKS

Exercise#6: The current through a 250-mH inductor takes the following values. Calculate he expression for the voltage across the inductor in each case. a. i̟(t) = 5 sin 25t A p. i(t) =- 10 cos 50t A E. i̟(t) = 25 cos(100t + TT/3) A 1. i̟(t) = 20 sin(10t – T/12) A