Explain Every Step of Below Code: public static void main(String args[]) { int count = 0; System.out.println("Enter a sentence :"); Scanner sc = new Scanner(System.in); String sentence = sc.nextLine(); for (int i=0 ; i
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Explain Every Step of Below Code:
public static void main(String args[])
{
int count = 0;
System.out.println("Enter a sentence :");
Scanner sc = new Scanner(System.in);
String sentence = sc.nextLine();
for (int i=0 ; i<sentence.length(); i++)
{
char ch = sentence.charAt(i);
if(ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u' )
{
System.out.print("");
}
else if(ch != ' ')
{ count++;}
}
System.out.println("Number of consonants in the given sentence is "+count);
}
Step by step
Solved in 3 steps
- Please make this java program work Instruction: Write a test program that inputs, sorts, outputs Integer and Float. And call the isEqualTo method. import java.util.*; public class Generics <E>{ public static < E > void printArray( E inputArray[] ) { // Display array elements for( E element : inputArray) { System.out.printf("%s ", element); } System.out.println(); } public static < E extends Comparable<E> > void selectionSort(E array[]){ int size = array.length; for (int i = 0; i < size-1; i++){ // Find the minimum element int min = i; for (int j = i+1; j < size; j++) if (array[j].compareTo(array[min]) < 0) min = j; // Swap the found minimum element with the first element E temp = array[min]; array[min] = array[i]; array[i] = temp; } } public static <…public class Soru32{ // Returns length of LCS for X[0..m-1], Y[0..n-1] static void lcs(String X, String Y, int m, int n) { int[][] L = new int[m+1][n+1]; // Following steps build L[m+1][n+1] in bottom up fashion. Note // that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1] for (int i=0; i<=m; i++) { for (int j=0; j<=n; j++) { if (i == 0 || j == 0) L[i][j] = 0; else if (X.charAt(i-1) == Y.charAt(j-1)) L[i][j] = L[i-1][j-1] + 1; else L[i][j] = Math.max(L[i-1][j], L[i][j-1]); } } // Following code is used to print LCS int index = L[m][n]; int temp = index; // Create a character array to store the lcs string char[] lcs = new char[index+1]; lcs[index] = '\u0000'; // Set the terminating character // Start from the right-most-bottom-most…public class Soru32{ // Returns length of LCS for X[0..m-1], Y[0..n-1] static void lcs(String X, String Y, int m, int n) { int[][] L = new int[m+1][n+1]; // Following steps build L[m+1][n+1] in bottom up fashion. Note // that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1] for (int i=0; i<=m; i++) { for (int j=0; j<=n; j++) { if (i == 0 || j == 0) L[i][j] = 0; else if (X.charAt(i-1) == Y.charAt(j-1)) L[i][j] = L[i-1][j-1] + 1; else L[i][j] = Math.max(L[i-1][j], L[i][j-1]); } } // Following code is used to print LCS int index = L[m][n]; int temp = index; // Create a character array to store the lcs string char[] lcs = new char[index+1]; lcs[index] = '\u0000'; // Set the terminating character // Start from the right-most-bottom-most…
- FOR JAVA Write a Java method that takes two 2 dimensional int arrays (a and b) and a 2 dimensional boolean array (c) where all three arrays have the same size. Your method should return an array (result) such that, if a partic- ular element in c is true, then the corresponding (same indexed) element in result must be the multiplication of the the corresponding elements of a and b. If the element in c is false, then the the corresponding element in result must be the negative of multiplication of the the corresponding element in a and b. For example ifa = {{1,2,3},{4,5}},b = {{1,2,1},{0,2}} andc = {{true,false,true},{false,true}}, then the result should be result={{1, -4, 3}{0, 10}}.please i have problem with run import java.util.*;public class Main{ public static void main(String args[]) { int[][] Arr=new int[2][3]; Random r=new Random(); for(int i=0;i<2;i++) { for(int j=0;j<3;j++) { Arr[i][j]=r.nextInt(100); } } System.out.println("Elements in the array:\n"); for(int i=0;i<2;i++) { for(int j=0;j<3;j++) { System.out.print(Arr[i][j]+","); } System.out.println(); } System.out.println("\nElements in the array after adding 8:\n"); for(int i=0;i<2;i++) { for(int j=0;j<3;j++) { Arr[i][j]+=5;…Implement the vacuum cleaning agent function in Python/Java for the scenario described below: Consider two-dimensional Boolean array of size m x n (m and n can each be equal to 4) where m is the number of rows, and n is the number of columns. Obtain numerical positive integer values for m and n as inputs from the user. Generate random numbers and scale them down to either a “0” or a “1” according to whether they represent “Clean” or “Dirty”, respectively. After filling the array with 0s or 1s, start at some random array position indicating the initial position of the vacuum cleaner. First check if at that current position, there is the presence of a “Dirt” or not determined by whether 0 or 1 is filled in at that initial position of the vacuum cleaner. If there is a “Dirt”, clean it, and if there is no “Dirt” do a No-operation. After this is done, generate random numbers modulo 4 to obtain random numbers 0, 1, 2, 3 indicating whether to take a left, right, up or down correspondingly. If…
- write a java program (method) to store all arrangments(permuations) of a given string in an array. note: Here it has to be mentioned that the permutations can also be of shorter length than the list of letters and that no letter is to be repeated. For example, if the initial list of letters is "STOP", then "TOP" and "TOPS" are both valid permutations, but "STOPS" isn't.Please implement in Java implement a keyed bag in which the items to be stored are strings (perhaps people’s names) and the keys are numbers (perhaps Social Security or other identification numbers). So, the in- sertion method has this specification: public void insert(String entry, int key);// Precondition: size( ) < CAPACITY, and the // bag does not yet contain any item// with the given key.// Postcondition: A new copy of entry has// been added to the bag, with the given key. When the programmer wants to remove or retrieve an item from a keyed bag, the key of the item must be specified rather than the item itself. The keyed bag should also have a boolean method that can be used to determine whether the bag has an item with a specified key. In a keyed bag, the pro- grammer using the class specifies a particular key when an item is inserted. Here’s an implementation idea: A keyed bag can have two private arrays, one that holds the string data and one that holds the corresponding…Fill the insertCommas method to recursively construct and return a string representation of the parameter num, including commas for every third decimal place. Ex. 157992546 >>>>> 157,992,546 import java.util.*; public class NumbersWithCommas{ public static String insertCommas(int num){ } public static void main(String[] args){ int numTests =(int)(Math.random() * 6) + 5; for (int i = 0; i < numTests; i++){ int num = (int)(Math.random() * Integer.MAX_VALUE); System.out.println(num + " >>>>> " + insertCommas(num)); } System.out.println(1000000 + " >>>>> " + insertCommas(1000000)); System.out.println(1001020 + " >>>>> " + insertCommas(1001020)); System.out.println(561010002 + " >>>>> " + insertCommas(561010002)); } }
- Write a short recursive Java method that determines if a string s is a palindrome, that is, it is equal to its reverse. Examples of palindromes include 'racecar' and 'mom'. Test the method by asking the user to provide string entries to be checked. Hint: Check the equality of the first and last characters and recur (but be careful to return the correct value for both odd and even-length strings).JAVA Implement the equals method of the Arrow class. Two arrows are equal when they have the same starting point and direction. public class Arrow{ private Point start; private String direction; /** Constructs an arrow. @param x the x-position @param y the y-position @param direction a compass direction N E S W NE NW SE SW */ public Arrow(int x, int y, String direction) { start = new Point(); start.move(x, y); this.direction = direction; } /** Checks whether this arrow is equal to another. @param otherObject another arrow @return true if this arrow and otherObject have the same position and direction. */ public boolean equals(Object otherObject) { /* code goes here */ }}import java.util.Random; class Main { public static void main(String[] args) { Random rand = new Random(); int a = new int[100]; for (int i = 0; i < 100; i++) { a[i] = rand.nextInt(100); } print(a); System.out.println("---"); quicksort(a, 0, a.length - 1); print(a); } public static void print(int[] a) { for (int x : a) { System.out.println(x); } } public static void swap(int[] a, int p1, int p2) { int temp = a[p1]; a[p1] = a[p2]; a[p2] = temp; } public static int partition(int[] a, int left, int right) { int pivot = right; int p1 = left; int p2 = pivot - 1; while (p2 >= p1) { if (a[p1] > a[pivot]) { swap(a, p1, p2); swap(a, p2, pivot); p2 = pivot - 1; } else { p1++; } } return pivot; } public static void quicksort(int[] a, int left, int right) { if (left < right) { int p = partition(a, left, right); quicksort(a, left, p - 1);…
