Explain how an internal node of a Binary Search Tree (BST) is deleted. Take note that after the deletion, the result is still a BST.
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Explain how an internal node of a Binary Search Tree (BST) is deleted. Take note that after the deletion, the result is still a BST.
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- Create a function that checks whether a binary tree is balanced. For the sake of this issue, a balanced tree is one in which the heights of the two subtrees of each node never deviate by more than one.78. What is the speciality about the inorder traversal of a binary search tree? a) It traverses in a non increasing order b) It traverses in an increasing order c) It traverses in a random fashion d) It traverses based on priority of the nodeWhat are the disadvantages of normal binary tree traversals?a) there are many pointers which are null and thus uselessb) there is no traversal which is efficientc) complexity in implementingd) improper traversals
- Suppose that instead of each node x keeping the attribute x.p, pointing to x’s parent, it keeps x.succ, pointing to x’s successor. Give pseudocode for SEARCH, INSERT, DELETE, and EDIT routine on a binary search tree T using this representation. These procedures should operate in time O(h), where h is the height of the tree T. (Hint: You may wish to implement a subroutine that returns the parent of a node.) Show these types of pseudocode using java. Data structures and algorithms332 File structures and DatabaseShow the B+-tree of order three (namely each node has a maximum of threekeys/descendents) that result from loading the following sets of keys in order:a. M, I, Tb. M, I, T, Q, L, H, R, E, Kc. M, I, T, Q, L, H, R, E, K, Pd. M, I, T, Q, L, H, R, E, K, P, C, AQues: Given a Binary Tree (BT), convert it to a Doubly Linked List(DLL) In-Place. The left and right pointers in nodes are to be used as previous and next pointers respectively in converted DLL. The order of nodes in DLL must be same as Inorder of the given Binary Tree. The first node of Inorder traversal (leftmost node in BT) must be the head node of the DLL. Find error in the following code: #include <bits/stdc++.h>using namespace std; // Tree Nodestruct Node{ int data; Node* left; Node* right;}; { Node* temp = new Node; temp->data = val; temp->left = NULL; temp->right = NULL; return temp;} // Function to Build TreeNode* buildTree(string str){ // Corner Case if(str.length() == 0 || str[0] == 'N') return NULL; // Creating vector of strings from input // string after spliting by space vector<string> ip; istringstream iss(str); for(string str; iss >> str; ) ip.push_back(str);…
- Ques: Given a Binary Tree (BT), convert it to a Doubly Linked List(DLL) In-Place. The left and right pointers in nodes are to be used as previous and next pointers respectively in converted DLL. The order of nodes in DLL must be same as Inorder of the given Binary Tree. The first node of Inorder traversal (leftmost node in BT) must be the head node of the DLL. Find error in the following code: #include <bits/stdc++.h> using namespace std; // Tree Node struct Node { int data; Node* left; Node* right; }; { Node* temp = new Node; temp->data = val; temp->left = NULL; temp->right = NULL; return temp; } // Function to Build Tree Node* buildTree(string str) { // Corner Case if(str.length() == 0 || str[0] == 'N') return NULL; // Creating vector of strings from input // string after spliting by space vector<string> ip; istringstream iss(str); for(string str; iss >> str;…Construct a Binary Search Tree (BST) using the data provided in shaded row and name it “BST-1”. 50 45 65 60 75 90 15 35 70 45 55 40 20 80 95 85 25 50 74 5 Provide answers to the following considering your constructed BST-1: Write a C++ code that finds and delete a node having exactly two Childs in a BST. Simulate your code on BST-1 and provide a step-by-step procedure to delete “15” and “75” from it.Write a program that inserts the following numbers into an initially empty BST such that the treeproduced is equivalent to binary search tree.50 30 25 75 82 28 63 70 4 43 74Hint: Calculate the mean value in method and put that value at the root and recursively build theleft and right subtree.A. Implement a function which, given a node in this binary search tree, prints out themaximum depths of its left and right subtrees.B. Implement a function to find the maximum value of all the nodes in the tree.C. Implement a function that balance the tree using appropriate rotation type and return theroot value.Note: You are not allowed to use any built-in Data Structure classes to implement abovescenario
- Question 1 When a binary search tree is balanced, it provides O(log2N) search, addition, and removal. True False Question 2 A depth-first traversal of a tree is also known as a level-order traversal. True False Question 3 Our BSTNode class is a self-referential class. True False Question 4 The contains method of our binary search tree examines every node in the tree before returning a result of false. True False Question 5 When a binary search tree is balanced, it provides O(N2) search, addition, and removal. True False Question 6 The number of nodes in a non-empty tree is equal to the number of nodes in its left subtree plus the number of nodes in its right subtree True False Question 7 A tree node's unique predecessor is its parent. True False Question 8 A tree node and all of its descendants form a subtree that is rooted at the node. True False Question 9 The number of different binary trees that can be made from 2 nodes that contain the key values 3 and 6 is 2.…1- Evaluate the following postfix expression of tree ABC*D/+ where A=2 B=3 C=4 D=6 2- What is a Binary Search Tree (BST)? Show the structure of the binary search tree after adding each ofthe following values in that order: 10, 25, 2, 4, 7, 13, 11, 22. What is the height of the created binarysearch tree?3- Construct a BST for the following numbers: 47, 55, 23, 17, 39, 11, 50, 9, 19, 74, 33, 28Show all the steps. Write its preorder traversal.Create a function to determine whether a binary tree is balanced. For the sake of this inquiry, a balanced tree is one where the heights of any given node's two subtrees never vary by more than one.