Explain in your own words, what happens with the below code: 1 first_list = [10, 20, 30 40] , 2 second_list = first_list second_list[3] = 400 3.
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- Given list: ( 10, 19, 31, 57, 69, 81, 82, 94 ) Which list elements will be compared to key 69 using binary search? Enter elements in the order checked.I have given you the linear search code example on the video and I want you to go through the code and adjust the code. In the following code, list consists of number 4 twice however when you execute this code you find only the first 4. Please adjust your code to find both 4’s on the list def linear_search(list1,key): for i in range(len(list1)): if key==list1[i]: print("Element is found at index", i) break else: print("The element is not found") list1=[4,5,10,4,9,21] key=int(input("Enter a key number: ")) linear_search(list1,key)Consider a list named NUM which elements are [3, 12, 5, 6, 8], which code will delete element last? a. NUM.append(8) b. NUM.pop() c. NUM.remove() d. NUM.insert()
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- how do i get this code to work properly function noSql(list, query) { var result=[]; var match = matchmaker(query); for(var i=0; i<list.length; i++) { var temp = list[i]; if(match(temp)) { result.push(temp); } } return result;} these are the instructions and examples somebody answered this incorrectly please do not copy that answer thank you!! noSql( list, query ) This function accepts a list of elements and an object known as the query. The method returns a list of all elements that have each of the key/value properties of the query. Examples var objects = [ { public : true, name : "Lion King" }, { public : true, name : 'Dumbo' }, { public : false, name : 'Lion King' }, { name : 'Xeon', rating : 5 } ]; noSql( objects, { public:true } ) should return this [ { public:true, name:'Lion King' }, { public:true, name:'Dumbo'}] noSql( objects, { name:'Lion King' } ) should return this [ { public:true, name:'Lion King' }, {…Replace XXX in the following function header for a doubly-linked list: ListInsertAfter(listName, currentNode, XXX) Group of answer choices headNode tailNode middleNode newNodeThe following code doesn't correctly return the index values of the minimum contiguous subsequence. Please modify it so that it does, with comments if possible. def minSumRec(a, left, right): if left == right: return [a[left], left, right] center = int((left + right) / 2) min_left_sum = minSumRec(a, left, center) min_right_sum = minSumRec(a, center + 1, right) min_left_border_sum, left_border_sum = 1e9, 0 for i in range(center, left - 1, -1): left_border_sum += a[i] if left_border_sum < min_left_border_sum: min_left_border_sum = left_border_sum min_right_border_sum, right_border_sum = 1e9, 0 for i in range(center + 1, right + 1): right_border_sum += a[i] if right_border_sum < min_right_border_sum: min_right_border_sum = right_border_sum min_border_sum = min_right_border_sum + min_left_border_sum minSum = min(min_left_sum[0], min_right_sum[0], min_border_sum) if minSum == min_left_sum: return min_left_sum if minSum == min_right_sum: return min_right_sum return…
- Suppose, alist is a 2-dimensional list. Which of the following options gives you the last element of this list? Question options: a. alist[ len(alist) - 1, len(alist) - 1 ] b. alist[ len(alist), len(alist) ] c. alist[ len(alist) - 1]Make Link list by displaying 0 9 0 7 2 0 0 1 and then perform addition and deletion functions.Write a line of code in R that will change the Location column of the tibble in my_Costco_list to an ordered factor where the order of the levels is in the following order: Clothes, Cereal, Refrigerated. Then write a line of code using the previous line to compute the minimum amount of items (not the number of different items) required in each location. my_Costco_list <- list(tibble(Item = c("Milk", "Coffee", "Lettuce","Pants"),Amount = c(4,1,2,2),Location = c("Refrigerated","Cereal","Refrigerated","Clothes")))