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S P(A/B) = A Let event A = Student belongs to at least one club on campus and event B = Student participates in team sports on campus P(B|A) = ANB At AnyTown Polytechnic College, 42% of students belong to a campus club, 38% of students participate in team sports, and 5% belong to at least one campus club and participate in team sports. Compute the probabilities requested below. Round all probabilities to four decimal places, as needed. P(An B)= P(ANB) = B

S P(A/B) = A Let event A = Student belongs to at least one club on campus and event B = Student participates in team sports on campus P(B|A) = ANB At AnyTown Polytechnic College, 42% of students belong to a campus club, 38% of students participate in team sports, and 5% belong to at least one campus club and participate in team sports. Compute the probabilities requested below. Round all probabilities to four decimal places, as needed. P(An B)= P(ANB) = B

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S P(A/B): A Let event A = Student belongs to at least one club on campus and event B = Student participates in team sports on campus P(B|A) = ANB At AnyTown Polytechnic College, 42% of students belong to a campus club, 38% of students participate in team sports, and 5% belong to at least one campus club and participate in team sports. Compute the probabilities requested below. Round all probabilities to four decimal places, as needed. P(ANB) = P(AnB): B
Transcribed Image Text:S P(A/B): A Let event A = Student belongs to at least one club on campus and event B = Student participates in team sports on campus P(B|A) = ANB At AnyTown Polytechnic College, 42% of students belong to a campus club, 38% of students participate in team sports, and 5% belong to at least one campus club and participate in team sports. Compute the probabilities requested below. Round all probabilities to four decimal places, as needed. P(ANB) = P(AnB): B
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Step 1

event A : student belongs to atleast one club on campusevent 

B : student participates in team sports on campus

P(A) = 0.42P(B) = 0.38P(A∩B) = 0.05

 
Step 2

(a) P(A|B) = P(A∩B)P(B) = 0.050.38 = 0.1316

(b) P(B|A) = P(A∩B)P(A) = 0.050.42 = 0.1190

(c) P(A∩B) = 0.05

(d) P(A∩B¯) = 1 - P(A∩B) = 1 - 0.05 = 0.95

Explain the probabilities, indicated below, you found in the previous problem. Assume you randomly select a student who [Select ] represents the probability that this student also [ Select ] on campus. P(A/B) Assume you randomly select a student who [Select ] on campus. campus. represents the probability that this student also [Select] on campus. P(B|A) campus. P(ANB) represents the probability that a randomly selected student [Select] on campus. on P(ANB) represents the probability that a randomly selected student [Select] on Dist Guic in resp impera chann e Marr Annu May 10 legacy- were re M h 2022 Enviro Gove Oct 24, have pre Ukraine O SI ht 424B4 Hilton W 64,102,5 offering. Ci http Summ Perspe Manag 10) Return money sa
Transcribed Image Text:Explain the probabilities, indicated below, you found in the previous problem. Assume you randomly select a student who [Select ] represents the probability that this student also [ Select ] on campus. P(A/B) Assume you randomly select a student who [Select ] on campus. campus. represents the probability that this student also [Select] on campus. P(B|A) campus. P(ANB) represents the probability that a randomly selected student [Select] on campus. on P(ANB) represents the probability that a randomly selected student [Select] on Dist Guic in resp impera chann e Marr Annu May 10 legacy- were re M h 2022 Enviro Gove Oct 24, have pre Ukraine O SI ht 424B4 Hilton W 64,102,5 offering. Ci http Summ Perspe Manag 10) Return money sa
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