Explain what it means to say that lim_ f(x) = 4 and lim f(x) = 1. x- 2* O As x approaches 2, f(x) approaches 1, but f(2) = 4. O As x approaches 2 from the left, f(x) approaches 4. As x approaches 2 from the right, f(x) approaches 1. O As x approaches 2, f(x) approaches 4, but f(2) = 1. O As x approaches 2 from the right, f(x) approaches 4. As x approaches 2 from the left, f(x) approaches 1. In this situation is it possible that lim_ f(x) exists? Explain. X-2 f(x) could have a hole at (2, 4) and be defined such that f(2) = 1. Yes, O Yes, f(x) could have a hole at (2, 1) and be defined such that f(2) = 4. O Yes, if f(x) has a vertical asymptote at x = 2, it can be defined such that lim_f(x) = 4, lim_f(x) = 1, and lim f(x) exists. x-2 x-2* X-2 No, lim f(x) cannot exist if lim_f(x) # lim_f(x). X-2
Explain what it means to say that lim_ f(x) = 4 and lim f(x) = 1. x- 2* O As x approaches 2, f(x) approaches 1, but f(2) = 4. O As x approaches 2 from the left, f(x) approaches 4. As x approaches 2 from the right, f(x) approaches 1. O As x approaches 2, f(x) approaches 4, but f(2) = 1. O As x approaches 2 from the right, f(x) approaches 4. As x approaches 2 from the left, f(x) approaches 1. In this situation is it possible that lim_ f(x) exists? Explain. X-2 f(x) could have a hole at (2, 4) and be defined such that f(2) = 1. Yes, O Yes, f(x) could have a hole at (2, 1) and be defined such that f(2) = 4. O Yes, if f(x) has a vertical asymptote at x = 2, it can be defined such that lim_f(x) = 4, lim_f(x) = 1, and lim f(x) exists. x-2 x-2* X-2 No, lim f(x) cannot exist if lim_f(x) # lim_f(x). X-2
Chapter6: Exponential And Logarithmic Functions
Section6.1: Exponential Functions
Problem 57SE: Repeat the previous exercise to find the formula forthe APY of an account that compounds daily....
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