Explain what the following SQL statements do. SELECT COUNT(PatientiD) FROM Patient_t AS PA INNER JOIN Physician_t AS P ON PAAdmitPhysld - P.PhysiD WHERE PhysLName=Jackson
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Q: This actually didnt work to resolve my problem... Heres what I have so far. CREATE TABLE Horse (…
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- Which of the following SQL statements is invalid and returns an error message? ALTER TABLE books ADD CONSTRAINT books_pubid_uk UNIQUE (pubid); ALTER TABLE books ADD CONSTRAINT books_pubid_pk PRIMARY KEY (pubid); ALTER TABLE books ADD CONSTRAINT books_pubid_nn NOT NULL (pubid); ALTER TABLE books ADD CONSTRAINT books_pubid_fk FOREIGN KEY (pubid) REFERENCES publisher (pubid); All of the above statements are invalid.This actually didnt work to resolve my problem... Heres what I have so far. CREATE TABLE Horse ( ID SMALLINT UNSIGNED AUTO_INCREMENT, RegisteredName VARCHAR(15), PRIMARY KEY (ID)); CREATE TABLE Student ( ID SMALLINT UNSIGNED AUTO_INCREMENT, FirstName VARCHAR(20), LastName VARCHAR(30), PRIMARY KEY (ID)); -- Your SQL statements go hereThe following two SQL statements will produce the same results. SELECT P_DESCRIPT, P_PRICE FROM PRODUCT WHERE P_CODE IN (SELECT P_CODE FROM LINE GROUP BY P_CODE HAVING COUNT(*) >=1); SELECT P_DESCRIPT, P_PRICE FROM PRODUCT WHERE EXISTS (SELECT P_CODE FROM LINE WHERE LINE.P_CODE=PRODUCT.P_CODE); Group of answer choices A) True B) False
- Express the following query in SQL using no subqueries and no set operations.select IDfrom studentexceptselect s_idfrom advisorwhere i_ID is not nullAnswer the given question with a proper explanation and step-by-step solution. sid name value working hours timestamp 14 temperatureΑΒΒ 47 20 11/10/22015 12:00:00 16 humidityBosch 51 200 11/11/22015 12:00:00 19 temperatureΑΒΒ 41 NULL 11/11/22015 12:00:00 20 temperatureΑΒΒ NULL 30 11/12/22015 12:00:00 Write sql statement that calculates the average temperature for the temperature sensor and it will be showed Write sql statement that will show all the fields of of the table in order not to have duplex values THE NULLS VALUES MUST BE EXCLUDED . PLEASE WRITE THE ANSWER IN PAPERGiven the following SQL statement, which statement is most accurate?SELECT customer# FROM customersJOIN orders USING(customer#)WHERE shipdate-orderdate IN(SELECT MAX(shipdate-orderdate) FROM ordersWHERE shipdate IS NULL);a. The SELECT statement fails and returns an Oracle error message.b. The outer query displays no rows in its results because the subquery passes a NULLvalue to the outer query.c. The customer number is displayed for customers whose orders haven’t yet shipped.d. The customer numbers of all customers who haven’t placed an order are displayed
- //trying to make recursive SQL statement to get the days of the week , can you tell me what does not work in this query: WITH cte_number (counter, weekday) AS(SELECT 0, Datename(DW,0) UNION ALLSELECTcounter+1, Datename(DW, counter+1)FROM cte_numberwhere counter<6) select weekday from cte_number; //thanks for you assistancethe question is : the SQL command to list the number of product sales (number of rows) and total sales by month, with subtotals by month and a grand total for all sales? i try to use SELECT TM_ MONTH , COUNT (*) AS NUMPROD , SUM ( SALE_UNITS * SALE_PRICE ) AS TOTSALESFROM DWDAYSALESFACT S JOIN DWTIME T ON S.TM_ID = T.TM_ID but ites incorrect ORA-00907: ¿¿¿¿¿00907. 00000 - "missing right parenthesis"*Cause: *Action: can the one answer me try the code it self and sure ites workable ? CREATE TABLE DWVENDOR ( V_CODE INTEGER PRIMARY KEY, V_NAME VARCHAR(35),V_AREACODE CHAR(3), V_STATE CHAR(2)); CREATE TABLE DWPRODUCT (P_CODE VARCHAR2(10) PRIMARY KEY,P_DESCRIPT VARCHAR2(35),P_CATEGORY VARCHAR(5),V_CODE NUMBER REFERENCES DWVENDOR); CREATE TABLE DWREGION ( REG_ID INTEGER PRIMARY KEY,REG_NAME VARCHAR(10)); CREATE TABLE DWCUSTOMER (CUS_CODE NUMBER PRIMARY KEY,CUS_LNAME VARCHAR(15),CUS_FNAME VARCHAR(15),CUS_INITIAL…Given the following SQL query: Student (sid, name, age, address) Book (bid, title, author) Checkout (sid, bid, date) SELECT S.name FROM Student S, Book B, Checkout C WHERE S.sid = C.sid AND B.bid = C.bid AND B.author = ’Olden Fames’ AND S.age > 12 AND S.age < 20 Write relational algebra query for the above SQL query. Using a drawing tool such as Visio or others (ex: https://www.draw.io/ is a free one) to draw initial relational algebra query trees for the query generated in question 1. Transform the initial query trees created above into a more efficient form (use the heuristic rules and show your steps (.
- in sql developer , irun a commend like this SELECT TM_ MONTH , COUNT (*) AS NUMPROD , SUM ( SALE_UNITS * SALE_PRICE ) AS TOTSALES FROM DWDAYSALESFACT S JOIN DWTIME T ON S.TM_ID = T.TM_ID GROUP BY ROLLUP ( T.TM_ MONTH_) ORDER BY T.TM_ MONTH its makeing erroe like 00907. 00000 - "missing right parenthesis"*Cause: *Action: can anyone fix this ,tell me whats the wrong of itWhat is the intepretation of the following SQL query in natural language (plain English)? SELECT F_Name ||’ ‘|| L_Name as “Employee Name”, Salary FROM Employee WHERE Salary> 20,000 AND Gender=’M’ GROUP BY Dep_No ORDER BY L_Name;For the table definition below, write a SQL UPDATE statement that changes all annual salaries to monthly salaries. CREATE TABLE Worker ( WORKER_ID INTEGER NOT NULL PRIMARY KEY AUTOINCREMENT, FIRST_NAME TEXT, LAST_NAME TEXT, SALARY DOUBLE, JOINING_DATE DATETIME, DEPARTMENT CHAR(25));