Write an SQL query to report all the classes that have at least five students. Return the result table in any order.
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I need the full code including (create table, insert...) and the output
To create a table named Enrollment, run following code:
CREATE TABLE Enrollment ( student varchar PRIMARY KEY, class varchar NOT NULL ); |
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- We need to create a database for the Circulation Department of a public library. The database will store information about the patrons, books, and circulation. It contains the following: 4 tables for the database: PATRON, BOOK_COPY, BOOK, and CHECKOUT. (Since a book may have multiple copies that may be purchased by the library at different time, it is better to have a BOOK_COPY table to avoid unnecessary data redundancy.) The data in the tables are as follows: PATRON table records a patron’s ID, name, address, phone number, and email address. BOOK table contains information such as author, title, publication date, subject, language, and a unique identifier (It can be the ISBN of the book) for each book. BOOK_COPY table records a unique identifier for each copy of a book, the date of purchase, and the identifier of the book from the BOOK table. CHECKOUT table records the date of check-out, patron’s ID, the…We need to create a database for the Circulation Department of a public library. The database will store information about the patrons, books, and circulation. It contains the following: 4 tables for the database: PATRON, BOOK_COPY, BOOK, and CHECKOUT. (Since a book may have multiple copies that may be purchased by the library at different time, it is better to have a BOOK_COPY table to avoid unnecessary data redundancy.) The data in the tables are as follows: PATRON table records a patron’s ID, name, address, phone number, and email address. BOOK table contains information such as author, title, publication date, subject, language, and a unique identifier (It can be the ISBN of the book) for each book. BOOK_COPY table records a unique identifier for each copy of a book, the date of purchase, and the identifier of the book from the BOOK table. CHECKOUT table records the date of check-out, patron’s ID, the…We need to create a database for the Circulation Department of a public library. The database will store information about the patrons, books, and circulation. It contains the following: 4 tables for the database: PATRON, BOOK_COPY, BOOK, and CHECKOUT. (Since a book may have multiple copies that may be purchased by the library at different time, it is better to have a BOOK_COPY table to avoid unnecessary data redundancy.) The data in the tables are as follows: PATRON table records a patron’s ID, name, address, phone number, and email address. BOOK table contains information such as author, title, publication date, subject, language, and a unique identifier (It can be the ISBN of the book) for each book. BOOK_COPY table records a unique identifier for each copy of a book, the date of purchase, and the identifier of the book from the BOOK table. CHECKOUT table records the date of check-out, patron’s ID, the…
- Below is a schema for an HR database:employee(empid, fname, lname, managerid, departmentid, employee_rank)It's an employee table, which has employee id, first name, last name, manager id (which is an employee id), department id, and employee_rank, such as VP, CEO, SVP, etc.Using SQL, answer this question (write a SQL query that answers this question) [tip: use a recursive query]. 10. For employee 42, find the path-of-managers directly to the CEO?A new movie theater has opened in your town and the owner needs a system that facilitates theReservation of seats in the cinema’s auditorium. Design a windows application Form thatFacilitates the reservation of tickets for this Movie Theater.Design and connect the following database using LINQ or Entity Framework for the givenscenario.Database:Movie (id (PK), name, description )ScheduleMovie (id (PK), movieID (FK), time, price)Seat (id (PK), number, rownumber, columnnumber)Reservation (id (PK), scheduledMovie(FK), seatnum(FK), customerId(FK), haspaidTicket)Customer (id (PK), email, name)The user of this application is a cinema staff, for example the admin and the Cashier.The Admin Panel The admin registers the cashiers and also, add new movies when released. The panel has various menus named Add, Remove, and detail Add menu has sub menu named AddMovie, and AddCashier. Remove menu has sub menunamed removeMovie and removeCashier. Click event raised on the click of AddMovie which…Indexing Consider a relational database that consists of the relational tables created by the following CREATE TABLE statements: CREATE TABLE PART( P_PARTKEY NUMBER(12) NOT NULL, P_NAME VARCHAR(55) NOT NULL, P_RETAILPRICE NUMBER(12,2) NOT NULL, CONSTRAINT PART_PEKEY PRIMARY KEY (P_PARTKEY) ); CREATE TABLE SUPPLIER( S_SUPPKEY NUMBER(12) NOT NULL, S_NAME CHAR(25) NOT NULL S_NATIONKEY NUMBER(12) NOT NULL, S_PHONE CHAR(15) NOT NULL, CONSTRAINT SUPPLIER_PKEY PRIMARY KEY (S_SUPPKEY) ); CREATE TABLE PARTSUPP( PS_PARTKEY NUMBER(12) NOT NULL, PS_SUPPKEY NUMBER(12) NOT NULL, PS_SUPPLYCOST NUMBER(12,2) NOT NULL, CONSTRAINT PARTSUPP_PKEY PRIMARY KEY (PS_PARTKEY, PS_SUPPKEY), CONSTRAINT PARTSUPP_FKEY1 FOREIGN KEY (PS_PARTKEY) REFERENCES PART(P_PARTKEY), CONSTRAINT PARTSUPP_FKEY2 FOREIGN KEY (PS_SUPPKEY) REFERENCES SUPPLIER(S_SUPPKEY) ); Determine what index should be created to improve the performance of the queries listed below in the best possible way. Consider each one of the…
- In this database we have users that can be two types students or instructors. They have groups and memberships. Any user can post and the post type can be video, photo or text. Here is the table structure: CREATE TABLE USER_ ( USER_ID INT NOT NULL AUTO_INCREMENT, CREATE_DATE DATE NOT NULL, PROF_DESC VARCHAR (100), PROF_PIC VARCHAR(40), LOCATION VARCHAR (40) NOT NULL, PRIMARY KEY (USER_ID) ); CREATE TABLE USER_INFO( USER_ID INT NOT NULL, SU_EMAIL CHAR(18), USER_FNAME VARCHAR(15), USER_LNAME VARCHAR (15), USER_DOB DATE, USER_GENDER CHAR(1), PRIMARY KEY (USER_ID), FOREIGN KEY (USER_ID) REFERENCES USER_(USER_ID) ON UPDATE CASCADE ); CREATE TABLE STUDENT ( SU_ID INT NOT NULL, USER_ID INT NOT NULL, YEAR_ VARCHAR (10), MAJOR VARCHAR (20), LOCATION VARCHAR (40) NOT NULL, PRIMARY KEY (SU_ID), FOREIGN KEY (USER_ID) REFERENCES USER_(USER_ID) ON UPDATE CASCADE ); CREATE TABLE INSTRUCTOR ( SU_ID INT NOT NULL, USER_ID INT NOT NULL, DEPARTMENT VARCHAR (40), INSTR_TYPE VARCHAR (40),…In this database we have users that can be two types students or instructors. They have groups and memberships. Any user can post and the post type can be video, photo or text. Here is the table structure: CREATE TABLE USER_ ( USER_ID INT NOT NULL AUTO_INCREMENT, CREATE_DATE DATE NOT NULL, PROF_DESC VARCHAR (100), PROF_PIC VARCHAR(40), LOCATION VARCHAR (40) NOT NULL, PRIMARY KEY (USER_ID) ); CREATE TABLE USER_INFO( USER_ID INT NOT NULL, SU_EMAIL CHAR(18), USER_FNAME VARCHAR(15), USER_LNAME VARCHAR (15), USER_DOB DATE, USER_GENDER CHAR(1), PRIMARY KEY (USER_ID), FOREIGN KEY (USER_ID) REFERENCES USER_(USER_ID) ON UPDATE CASCADE ); CREATE TABLE STUDENT ( SU_ID INT NOT NULL, USER_ID INT NOT NULL, YEAR_ VARCHAR (10), MAJOR VARCHAR (20), LOCATION VARCHAR (40) NOT NULL, PRIMARY KEY (SU_ID), FOREIGN KEY (USER_ID) REFERENCES USER_(USER_ID) ON UPDATE CASCADE ); CREATE TABLE INSTRUCTOR ( SU_ID INT NOT NULL, USER_ID INT NOT NULL, DEPARTMENT VARCHAR (40), INSTR_TYPE VARCHAR (40),…Creat a query for the following in miscrosoft access d. Produce the total payments received by each business on behalf of their employees. Name this query Q4 – TotalByBusiness. e. Create a query that prompts you (the user) for your first/last name and produces your client number, your first and last names, the salary deduction along with the total premium. Also include a calculated field named ‘Excess’ to subtract the total premium from your salary deduction.
- /* Created with SQL Script Builder v.1.5 */ /* Type of SQL : SQL Server */ CREATE TABLE EMPLOYEE ( EMP_CODE int, EMP_TITLE varchar(4), EMP_LNAME varchar(15), EMP_FNAME varchar(15), EMP_INITIAL varchar(1), EMP_DOB datetime, JOB_CODE varchar(5), STORE_CODE int ); INSERT INTO EMPLOYEE VALUES('1','Mr.','Williamson','John','W','5/21/1964','SEC','3'); INSERT INTO EMPLOYEE VALUES('2','Ms.','Ratula','Nancy','','2/9/1969','MGR','2'); INSERT INTO EMPLOYEE VALUES('3','Ms.','Greenboro','Lottie','R','10/2/1961','GEN','4'); INSERT INTO EMPLOYEE VALUES('4','Mrs.','Rumpersfro','Jennie','S','6/1/1971','GEN','5'); INSERT INTO EMPLOYEE VALUES('5','Mr.','Smith','Robert','L','11/23/1959','GEN','3'); INSERT INTO EMPLOYEE VALUES('6','Mr.','Renselaer','Cary','A','12/25/1965','GEN','1'); INSERT INTO EMPLOYEE VALUES('7','Mr.','Ogallo','Roberto','S','7/31/1962','MGR','3'); INSERT INTO EMPLOYEE VALUES('8','Ms.','Johnsson','Elizabeth','I','9/10/1968','SEC','1'); INSERT INTO EMPLOYEE…/* Created with SQL Script Builder v.1.5 */ /* Type of SQL : SQL Server */ CREATE TABLE EMPLOYEE ( EMP_CODE int, EMP_TITLE varchar(4), EMP_LNAME varchar(15), EMP_FNAME varchar(15), EMP_INITIAL varchar(1), EMP_DOB datetime, JOB_CODE varchar(5), STORE_CODE int ); INSERT INTO EMPLOYEE VALUES('1','Mr.','Williamson','John','W','5/21/1964','SEC','3'); INSERT INTO EMPLOYEE VALUES('2','Ms.','Ratula','Nancy','','2/9/1969','MGR','2'); INSERT INTO EMPLOYEE VALUES('3','Ms.','Greenboro','Lottie','R','10/2/1961','GEN','4'); INSERT INTO EMPLOYEE VALUES('4','Mrs.','Rumpersfro','Jennie','S','6/1/1971','GEN','5'); INSERT INTO EMPLOYEE VALUES('5','Mr.','Smith','Robert','L','11/23/1959','GEN','3'); INSERT INTO EMPLOYEE VALUES('6','Mr.','Renselaer','Cary','A','12/25/1965','GEN','1'); INSERT INTO EMPLOYEE VALUES('7','Mr.','Ogallo','Roberto','S','7/31/1962','MGR','3'); INSERT INTO EMPLOYEE VALUES('8','Ms.','Johnsson','Elizabeth','I','9/10/1968','SEC','1'); INSERT INTO EMPLOYEE…/* Created with SQL Script Builder v.1.5 */ /* Type of SQL : SQL Server */ CREATE TABLE EMPLOYEE ( EMP_CODE int, EMP_TITLE varchar(4), EMP_LNAME varchar(15), EMP_FNAME varchar(15), EMP_INITIAL varchar(1), EMP_DOB datetime, JOB_CODE varchar(5), STORE_CODE int ); INSERT INTO EMPLOYEE VALUES('1','Mr.','Williamson','John','W','5/21/1964','SEC','3'); INSERT INTO EMPLOYEE VALUES('2','Ms.','Ratula','Nancy','','2/9/1969','MGR','2'); INSERT INTO EMPLOYEE VALUES('3','Ms.','Greenboro','Lottie','R','10/2/1961','GEN','4'); INSERT INTO EMPLOYEE VALUES('4','Mrs.','Rumpersfro','Jennie','S','6/1/1971','GEN','5'); INSERT INTO EMPLOYEE VALUES('5','Mr.','Smith','Robert','L','11/23/1959','GEN','3'); INSERT INTO EMPLOYEE VALUES('6','Mr.','Renselaer','Cary','A','12/25/1965','GEN','1'); INSERT INTO EMPLOYEE VALUES('7','Mr.','Ogallo','Roberto','S','7/31/1962','MGR','3'); INSERT INTO EMPLOYEE VALUES('8','Ms.','Johnsson','Elizabeth','I','9/10/1968','SEC','1'); INSERT INTO EMPLOYEE…