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Explain why Newton's method doesn't work for finding the root of the equation x3 - 3x +1 = 0 if the initial approximation is chosen to be x1 = 1. (x) = x³ - 3x + 1 = f'(x) =| If x, = 1, then f'(x1) =| and the tangent line used for approximating x2 is --Select-- v. Attempting to find x2 results in trying to --Select--- v by zero.

Explain why Newton's method doesn't work for finding the root of the equation x3 - 3x +1 = 0 if the initial approximation is chosen to be x1 = 1. (x) = x³ - 3x + 1 = f'(x) =| If x, = 1, then f'(x1) =| and the tangent line used for approximating x2 is --Select-- v. Attempting to find x2 results in trying to --Select--- v by zero.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.2: Trigonometric Equations
Problem 61E
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Explain why Newton's method doesn't work for finding the root of the equation x3 - 3x + 1 = o if the initial approximation is chosen to be x1 = 1. f(x) = x3 - 3x + 1 = f'(x) = If x1 = 1, then f'(x1) = and the tangent line used for approximating x2 is ---Select-- v Attempting to find x2 results in trying to ---Select--- v by zero.
Transcribed Image Text:Explain why Newton's method doesn't work for finding the root of the equation x3 - 3x + 1 = o if the initial approximation is chosen to be x1 = 1. f(x) = x3 - 3x + 1 = f'(x) = If x1 = 1, then f'(x1) = and the tangent line used for approximating x2 is ---Select-- v Attempting to find x2 results in trying to ---Select--- v by zero.
Use Newton's method to find all solutions of the equation correct to six decimal places. (Enter your answers as a comma-separated list.) 4 cos(x) = x + 1 X =
Transcribed Image Text:Use Newton's method to find all solutions of the equation correct to six decimal places. (Enter your answers as a comma-separated list.) 4 cos(x) = x + 1 X =
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