Explain why Newton's method doesn't work for finding the root of the equation x3 − 3x + 3 = 0 if the initial approximation is chosen to be x1 = 1. f(x) = x3 − 3x + 3 ⇒ f '(x) = . If x1 = 1, then f '(x1) = and the tangent line used for approximating x2 is ---Select--- horizontal vertical . Attempting to find x2 results in trying to ---Select--- divide multiply by zero.
Explain why Newton's method doesn't work for finding the root of the equation x3 − 3x + 3 = 0 if the initial approximation is chosen to be x1 = 1. f(x) = x3 − 3x + 3 ⇒ f '(x) = . If x1 = 1, then f '(x1) = and the tangent line used for approximating x2 is ---Select--- horizontal vertical . Attempting to find x2 results in trying to ---Select--- divide multiply by zero.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Explain why Newton's method doesn't work for finding the root of the equation
x3 − 3x + 3 = 0
if the initial approximation is chosen to be
x1 = 1.
f(x) = x3 − 3x + 3 ⇒ f '(x) =
.
If
x1 = 1,
then
f '(x1) =
and the tangent line used for approximating
x2
is ---Select--- horizontal vertical . Attempting to find
x2
results in trying to ---Select--- divide multiply by zero.Expert Solution
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