Explain why the following justification is incorrect: To evaluate the limit of the function x² + y² 2 lim (x,y) →(0,0) 1+ y² we can approach the point (0,0) along different paths and see if the limit is the same regardless of the path taken. First, let's consider the path along the x-axis ($y = 0$). We have: x² + 0² lim (,0) (0,0) 1+0² lim (x,0) (0,0) 1 Next, let's consider the path along the y-axis ($x = 0$). We have: 0² + y² lim (0,y) →(0,0) 1+ y² = 0. y² lim (0,y) (0,0) 1+ y² = 0. Since the limit is 0 along both paths, we can conclude that the limit of the given function as (x, y) approaches (0, 0) is 0. Enter your answer here
Explain why the following justification is incorrect: To evaluate the limit of the function x² + y² 2 lim (x,y) →(0,0) 1+ y² we can approach the point (0,0) along different paths and see if the limit is the same regardless of the path taken. First, let's consider the path along the x-axis ($y = 0$). We have: x² + 0² lim (,0) (0,0) 1+0² lim (x,0) (0,0) 1 Next, let's consider the path along the y-axis ($x = 0$). We have: 0² + y² lim (0,y) →(0,0) 1+ y² = 0. y² lim (0,y) (0,0) 1+ y² = 0. Since the limit is 0 along both paths, we can conclude that the limit of the given function as (x, y) approaches (0, 0) is 0. Enter your answer here
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
Problem 99E: Determine if the statemment is true or false. If the statement is false, then correct it and make it...
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